Answer:
10. (5, 6)
11. (1, 2)
12. (7, 8)
13. (10, 11)
14. (27, 28)
15. (11, 12)
Step-by-step explanation:
If you're not familiar with the squares of small integers, your calculator can help you figure this.
10. √28 ≈ 5.291 . . . . between 5 and 6
11. √3 ≈ 1.732 . . . . between 1 and 2
12. √59 ≈ 7.681 . . . . between 7 and 8
13. √115 ≈ 10.724 . . . between 10 and 11
14. √772 ≈ 27.785 . . . . between 27 and 28
15. √140 ≈ 11.832 . . . . between 11 and 12
2
3
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4
2
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9
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4
Step-by-step explanation:
Its impossible there is no way to solve it because x+3.5= y no number can make 12 if one number is 3.5 ft longer than the other Ignore this i dont feel like erasing this part.
144 in. 42 in. greater than the other 42 + x = y Nvm if you convert the numbers too in. the numbers are 93 + 51 = 144 and if you convert it back it would be
7.75 + 4.25 = 12
The mean is calculated by adding up all of the given numbers and dividing by the number of numbers.
Lets, for ease of understanding, say that the first three number were 64...
Mean=(64+64+64)/3=192/3=64
Now, lets solve for the mean where 'x' is the unknown fourth number and 128 is the mean. (since, the answer said that when the fourth number was added the mean, 64, was doubled '64*2=128')
128=(64+64+64+x)/4
128=(192+x)/4
Multiply both sides by 4
512=192+x
subtract 192 from both sides
320=x
The missing number is 320..
Now lets double check our work.
Mean=(64+64+64+320)/4=512/4=128
Answer=320