<u>Given </u><u>:</u><u>-</u>
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
- The equation in slope intercept form .
<u>Answer</u><u> </u><u>:</u><u>-</u>
From the given graph , we can see that the line passes through y axis at (0,5) . So the y intercept is 5 . And the slope of the line is 5/2 = 2.5 . So ,
y intercept = 5 .
slope = 5/2 .
Now here we can use the slope intercept form as ,
y = mx + c
y = 5/2x + 5
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>y </u><u>=</u><u> </u><u>5</u><u>/</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>5</u><u>.</u>
We know that
points are
x intercept
A (4,0)
y intercept
B (0,11)
step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4
with m and the point B (0,11)
y-y1=m*(x-x1)y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11
the answer is
the formula of the function is y=-(11/4)x+11
see the attached figure
For this case we must indicate which of the equations shown can be solved using the quadratic formula.
By definition, the quadratic formula is applied to equations of the second degree, of the form:
Option A:
Rewriting we have:
This equation can be solved using the quadratic formula
Option B:
Rewriting we have:
It can not be solved with the quadratic formula.
Option C:
Rewriting we have:
This equation can be solved using the quadratic formula
Option D:
Rewriting we have:
It can not be solved with the quadratic formula.
Answer:
A and C
Answer:
4cos4x
Step-by-step explanation:
let's use cos
amplitude=4
period=pi/2
2pi/x=pi/2
x=4
no phase shift
y=4cos4x
pic from desmos
Answer: x= -6; y= -1
Step-by-step explanation:
-4x + y = 23
4x - 9y = - 15
-4x + y = 23
y = 23 + 4x [Add 4x to both side]
4x - 9(23 + 4x) = - 15
4x - 207 - 36x = - 15
-32x - 207 = -15
-32x = 192 [Add 207 to both side]
x = -6 [Divide -32 from both side]
-4x + y = 23
-4(-6) + y = 23 [Plug in -6 for x]
24 + y = 23 [Subtract 24 from both side]
y = -1
