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Before you make an offer on a home, you should first make sure your mortgage loan application has received a

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After you submit your loan application, the lender does an extensive check on your finances and credit record. If everything checks out, the lender will state the exact amount they're willing to loan you. The preapproval is good for a set amount of time, usually 60–90 days.

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Multiply out and simplify: (x + 6)(x - 2)

Gwar [14]

Answer:

x squared+4x−12

Step-by-step explanation:

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2 years ago

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What is the square root of 8 and why?

kicyunya [14]

Rewrite 88 as 22⋅222⋅2.Factor 44 out of 88.√4(2)4⁢2Rewrite 44 as 2222.√22⋅222⋅2Pull terms out from under the radical.2√22⁢2The result can be shown in both exact and decimal forms.Exact Form:2√22⁢2Decimal Form:2.82842712…

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2 years ago

How do i solve this

MAXImum [283]

Answer:

x = 0, x = 3

Step-by-step explanation:

Given

- 4x² = - 12x ( add 12x to both sides )

- 4x² + 12x = 0 ← factor out - 4x from each term

- 4x(x - 3) = 0

Equate each factor to zero and solve for x

- 4x = 0 ⇒ x = 0

x - 3 = 0 ⇒ x = 3

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2 years ago

Ari thinks the perfect milkshake has 3 ounces of caramel for every 5 scoops of ice cream. Freeze Zone makes batches of milkshake

aksik [14]

A. They have too much caramel

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3 years ago

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In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg.

muminat

Answer:

Trial- 2 shows the conservation of momentum in a closed system.

Step-by-step explanation:

Given: Mass of balls are $m= 1.0\ kg$

Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.

Let initial velocity of ball $A\ is\ u_1$
Initial velocity of ball $B\ is\ u_2$
Final velocity of ball $A\ is\ v_1$
Final velocity of ball $B\ is\ v_2$
Momentum before collision $= mu_1+mu_2$
Momentum after collision $=mv_1+mv_2$

Now, According to conservation of momentum.

Momentum before collision = Momentum after collision

$mu_1+mu_2=mv_1+mv_2$

We will plug each trial to this equation.

Trial 1

$mu_1+mu_2=mv_1+mv_2\\1.0(1)+1.0(-2)=1.0(-2)+1.0(-1)\\1-2=-2-1\\-1=-3$

Trial 2

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1.5)=1.0(-.5)+1.0(-\.5)\\.5-1.5=-.5-.5\\-1=-1$

Trial 3

$mu_1+mu_2=mv_1+mv_2\\1.0(2)+1.0(1)=1.0(1)+1.0(-2)\\2+1=1-2\\3=-1$

Trial 4

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1)=1.0(1.5)+1.0(-1.5)\\.5-1=1.5-1.5\\-.5=0$

We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.

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3 years ago