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3 years ago

Math help please please

Mathematics

1 answer:

Vika [28.1K]3 years ago

6 0

Answer:

3(3x+1) (2x-1)

Step-by-step explanation:

18x^2 -3x-3

Factor out a 3

3(6x^2 -x-1)

3(3x+1) (2x-1)

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Solve for x. 4(x - 1) + 3x = 31*

lisabon 2012 [21]

Answer:

x=5

Step-by-step explanation:

4(−1)+3=31

4−4+3=31

6 0

2 years ago

He has 65 tomato plants already.

miskamm [114]

Answer:

ineed po ng pic na sasagutan nyo po and i answer this quest

5 0

3 years ago

Read 2 more answers

Hi- I need help please to get my HS diploma...did not graduate :(

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

first for the easy one : the curve line is dotted, if the line points are NOT part of the solution. and it is solid, if the points are included.

you know what the curve line indicates ? it indicates the points for which there is equality.

so, if there is a ">=" or "<=" relation, then that includes equality, and the curve is solid.

if there is only a true inequality ("<", ">"), then the curve is dotted, as the equality is not included.

so, I how this is now really clear.

in our case here (I suspect it really looks like this)

y + 4x <= x² + 2

we have a "<=" sign, so, the curve is ..., well ? ... well ? ...

well ? ... well ? ... solid !

and we still treat inequalities as much as possible as regular equalities.

so,

y <= x² - 4x + 2 (after subtracting 4x from both sides).

and now you see it, right ?

all y values that are smaller or equal to the quadratic expression.

SMALLER ! so, BELOW the curve (as the smaller y values are represented by the lower part of the y-axis).

4 0

2 years ago

1. The diagonal of a quadrilateral

zalisa [80]

Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.

Given:

Length of the diagonal of a quadrilateral = 8.5 cm

Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.

To find:

The area of the quadrilateral.

Solution:

Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.

According to the question,

Triangle 1 : Base = 8.5 cm and Height = 3.5 cm

Triangle 2 : Base = 8.5 cm and Height = 4.5 cm

Area of a triangle is

$Area=\dfrac{1}{2}\times base \times height$

Using this formula, we get

$Area(\Delta 1)=\dfrac{1}{2}\times 8.5\times 3.5$

$Area(\Delta 1)=14.875$

and

$Area(\Delta 2)=\dfrac{1}{2}\times 8.5\times 4.5$

$Area(\Delta 2)=19.125$

Now, area of the quadrilateral is

$Area=Area(\Delta 1)+Area(\Delta 2)$

$Area=14.875+19.125$

$Area=34$

Therefore, the area of the quadrilateral is 34 cm².

6 0

2 years ago

If one factor of 6x^2+5x-6 is 3x-2, whats the other factor

nekit [7.7K]

Answer:

the answer is -3x+2 good luck

7 0

2 years ago

Math help please please ​

Math help please please