How many kilometers is 23 miles
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
∠1 and ∠2 are vertical angles.
∠1 = ∠2
<u>Part A:</u>
<u></u>
Create an equation and solve for x.
20x + 21 = 30x - 29
Add 29 and -20x on both sides.
20x + 21 + 29 - 20x = 30x - 29 + 29 - 20x
Simplify the equation.
50 = 10x
Divide both sides by 10.
=
Simplify the equation.
5 = x
Switch sides.
x = 5
<u>Part B:</u>
<u></u>
Let x = 5
20(5) + 21
Distribute.
100 + 21
Add.
= 121
Since both angles are vertical angles, they are equal.
∠1 = 121°
∠2 = 121°
Answer:
Maximum (250,125) Answer
Step-by-step explanation:
This is more of a graphing problem than it is anything else.
Begin by graphing all 4 given equations.
When you do that, mark the intersection points of at least 2 lines. In this case it is exactly 2 lines for each intersecting point.
6x + 4y <= 2000 and 2x + 4y <= 1000 intersect at (250,125)
x=>0 and y=>0 intersect at (0,0)
6x + 4y <=2000 and x => 0 intersect at 333.333
2x + 4y <=1000 and y>=0 intersect at 0,250.
Any other intersection points fall outside the range of the givens. The shaded part we are interested in is sort of a very dark green/blue. It is the interior of the quadrilateral determined by the 4 vertices that are marked.
Now all you have to do is determine the maximum point using P=15x + 12y
For 0,0 P = 15*0 + 12,0 = 0
For 0,250 P = 15*0 + 12*250 = 3000
For 333.3333,0 P = 15*333.3333 + 12*0 = 5000 rounded.
For 250,125 P = 15*250 + 12*125 = 5250 Which is the maximum
Answer (250,125) produces the maximum value Answer
