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Studentka2010 [4]
3 years ago
11

Express the series using sigma notation 6b + 3b + 0 + (-3b) + (-6b).

Mathematics
1 answer:
zvonat [6]3 years ago
6 0

Answer:

0

Step-by-step explanation:

6b+3b+0+(-3b)+(-6b)\\6b+3b-3b-6b\\6b-6b\\0

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If you place $1,000.00 in a savings account with an interest rate of 5.25%/month, how much should you earn in interest at the en
Doss [256]
It's al little over 190. you just divide the 1000 by the 5.25%.
4 0
3 years ago
Help with this pleaseee​
Savatey [412]

Answer:

Sum of 100 terms of the sequence = 15050

Step-by-step explanation:

Given expression which represents a sequence is,

\sum_{r=1}^{100}(3r-1)

So the sequence will be,

2, 5, 8, 11, 14..........

So, the given sequence is an arithmetic sequence with,

First term of the sequence 'a' = 2

Common difference 'd' = 5 - 2 = 3

Sum of 'n' terms of an arithmetic sequence is given by,

S_n=\frac{n}{2}[2a+(n-1)d]

Here, n = number of terms

a = first term

d = common difference

S_{100} = \frac{100}{2}[2(2)+(100-1)(3)]

      = 50[4 + 297]

      = 15050

Therefore, sum of 100 terms of the sequence = 15050  

3 0
3 years ago
A heap of grain is shaped as a cone ADCF with height 5 m and base radius 2 m, as shown on the diagram. A and C are points on the
hoa [83]

Answer:

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone ≈ 12.57 m²

Step-by-step explanation:

The given parameters are;

The height of the cone = 5 m

The base radius of the cone  = 2 m

The angle which the A\hat OC = 120°

Therefore, we have;

The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone

The angle between [CF]  and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°  

∴ The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone = 68.2°

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57

The area of the base of the cone ≈ 12.57 m².

8 0
3 years ago
On a coordinate plane, two parabolas open up. The solid-line parabola, labeled f of x, goes through (negative 2, 4), has a verte
34kurt

Answer:

y = (x+4)^{2}+6

Step-by-step explanation:

The parabola with vertex at point (h,k) is described by the following model:

y - k = C\cdot (x-h)^{2}

The equation which satisfies the conditions described above:

y - 6 = (x+4)^{2}

y = (x+4)^{2}+6

The two points are evaluated herein:

x = -6

y =(-6+4)^{2}+6

y = (-2)^{2}+6

y = 4 + 6

y = 10

x = -2

y = (-2+4)^{2}+6

y = 2^{2} + 6

y = 4 + 6

y = 10

The equation of the translated function is y = (x+4)^{2}+6.

4 1
3 years ago
Read 2 more answers
Square root of 9/16
Aleksandr-060686 [28]
\sqrt{ \frac{9}{16} } = \frac{ \sqrt{9} }{ \sqrt{16} } = \frac{3}{4}
5 0
4 years ago
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