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max2010maxim [7]
3 years ago
13

What is the axis of symmetry in a parabola khanacademy?

Mathematics
1 answer:
elena-s [515]3 years ago
7 0
The axis of symmetry in a parabola is a line that's vertical that divides into 2 congruent halves. 
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Find the slope and y-intercept of (x+2)(x+3)=(x-2)(x-3)+y​
allochka39001 [22]

Answer:

Slope: 10

y-intercept: (0,0)

5 0
3 years ago
Read 2 more answers
6xy (x 2 - xy + y 2 )
Liono4ka [1.6K]

(if 2 is a square)

6xy ( x2 - xy + y2)

= 6x3y - 6x2y2 - 6xy3 --------------the threes and twos on this line are squares and cubics. the six is just a whole number


6 0
3 years ago
The general solution to the second-order differential equation y′′+10y=0 is in the form y(x)=c1cosβx+c2sinβx. Find the value of
allsm [11]

Answer:β=√10 or 3.16 (rounded to 2 decimal places)

Step-by-step explanation:

To find the value of β :

  • we will differentiate the y(x) equation twice to get a second order differential equation.
  • We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β

y(x)=c1cosβx+c2sinβx

we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.

Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate  βx in each case and multiply with the differential of c1cosx and c2sinx respectively.

lastly the differential of sinx= cosx and for cosx = -sinx.

Knowing all these we can proceed to solving the problem.

y=c1cosβx+c2sinβx

y'= β×c1×-sinβx+β×c2×cosβx  

y'=-c1βsinβx+c2βcosβx

y''=β×-c1β×cosβx + (β×c2β×-sinβx)

y''= -c1β²cosβx -c2β²sinβx

factorize -β²

y''= -β²(c1cosβx +c2sinβx)

y(x)=c1cosβx+c2sinβx

therefore y'' = -β²y

y''+β²y=0

now we compare this with the second order D.E provided in the question

y''+10y=0

this means that β²y=10y

β²=10

B=√10  or 3.16(2 d.p)

5 0
3 years ago
Please help with this question
NemiM [27]
Use the equation a^2 + b^2 = c^2.

225 + 1296 = c^2
1596 = c^2
Square root both

39 = c

4 0
3 years ago
What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?
anyanavicka [17]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f( - 4) = 4( - 4) + 9 =  - 7

_________________________________

f( - 2) = 4( - 2) + 9 = 1

_________________________________

f(0) = 4(0) + 9 = 9

_________________________________

f(2) = 4(2) + 9 = 17

_________________________________

Thus ;

R = { - 7 , 1 , 9 , 17 }

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The correct answer is (( D )) .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

3 0
2 years ago
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