Question

Dhani has 4 cards numbered 1 through 4. He removes 2 cards at random and adds their values.

Answer 1

Answer:

$2/3$

Step-by-step explanation:

The total number of sums (not distinct) is $4\cdot 3=12$, because we're removing without replacement.

Count the sums that fit the stipulation (sum $\leq$ 5):

$1,2,\\2,1\\1,3\\3,1\\1, 4\\4, 1\\2, 3, \\3,2$

There are 8 sums that work. Therefore, the desired answer is $\frac{8}{12}=\boxed{\frac{2}{3}}$