Carl throws a single die twice in a row. For the first throw, Carl rolled a 2; for the second throw he rolled a 4. What is the p
1 answer:
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Answer: a) +
= 1
b) The distance of two foci is 85.4 feet
c) Area = 3502.67 square feet
Step-by-step explanation: a) An ellipse has the equation in the form of:
+
= 1, where a is the horizontal axis and b is the vertical axis.
For the Statuary Hall, a = = 48.5 and b =
= 23, so the equation will be
+
= 1.
b) To determine the distance of the foci, we have to calculate 2c, where c is the distance between one focus and the center of the ellipse. To find c, as a, b and c create a triangle with a as hypotenuse:
=
c =
c = 42.7
The distance is 2c, so 2·42.7 = 85.4 feet.
The two foci are 85.4 feet apart.
c)The area of an ellipse is given by:
A = a.b.π
A = 48.5 · 23 · 3.14
A = 3502.67 ft²
The area of the floor room is 3502.67ft².
Using the mid-point concept, it is found that the coordinates of B are (-2, -1).
- The mid-point of two points is the <u>mean of the coordinates of each point</u>.
In this problem:
- The points are: A(2, -5) and B(x,y).
- The mid-point is (0, -3).
Applying the concept for both the x and y-coordinates, we have that:
The coordinates of B are (-2, -1).
To learn more about the mid-point concept, you can take a look at brainly.com/question/10956693