Answer:
Well...when dealing with problems related to blood pressure like hypertension etc., as a medical specialist, we mostly consider exercise plan that include aerobic and cardiovascular exercises. The main target of these exercises are heart muscles because anomaly in the rhythm associated with heart muscles are associated with major heart diseases and blood pressure problems.
The heart rate and blood pressure act in a way to compensate each other. When the heart rate rises, the pulse rate doesn't get rise in the same way because arteries dilate and expand to compensate the heart output and the blood pressure remains in range. It's action is like a buffer in chemistry. The rhythm of cardiac cycles are highly associated with the action and output given by cardiac muscles. Although they bare involuntary yet there strength is crucial for the proper rhythm of heart's cardiac cycle.
Answer:
in the qoridndt plan it woud grap diferint
Explanation:
What grade biology is it?
That was the picture, here is the math. Rather than computing all the individual probabilities then multiplying them out, I prefer to compute the probability distribution of each generation and pass it along that way.
The grandfather's probability of being Tt is 2/3. *If he is Tt* each of his offspring (2a and 2b) has a 1/2 probability of being Tt as well. So overall, the probability for each of his offspring being Tt is 2/3 * 1/2 = 1/3.
The offspring are independent events (one would hope) so the probability of both his offspring 2a and 2b being Tt is 1/3 * 1/3 = 1/9.
If 2a is Tt, 2a and TT spouse have a 1/2 probability of producing a Tt offspring. The same argument applies to 2b. The probability that 2a and 2b produce Tt offspring is 1/2 * 1/2 = 1/4. But the probability that 2a and 2b were Tt is 1/9 as calculated above. So the probability that 3a and 3b are both Tt is 1/4 * 1/9 = 1/36. So there is a 1/36 chance that 3a and 3b both are carriers.
If 3a and 3b have a child and if they are both Tt carriers, the probability that they will have a tt child is 1/4. The probability that 3a and 3b are both carriers is 1/36. So to obtain the probability of a tt child is 1/4 * 1/36 = 1/144.
I hope that this is the answer that you were looking for and it has helped you.
