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matrenka [14]
3 years ago
5

Which equation could determine exactly how many times Haley can go through the funhouse?

Mathematics
1 answer:
pochemuha3 years ago
4 0

Answer:

A. 49.79 = 1.19 + 0.25t

Step-by-step explanation:

One-time entrance fee to be paid by Haley as initial fee = $1.19

Going through the fun house each time would attract an additional fee of $0.25 each time they go through the fun house.

If Haley has $49.79, the number of times (t) Haley can go through can be expressed as:

Total amount Haley has = initial fee/entrance fee + additional fee per each time Haley goes through the fun house

The equation would be:

49.79 = 1.19 + 0.25t

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2. The rectangular floor of a garage has an area of 198 square feet. Andy knows that the floor is 7
Charra [1.4K]

Answer:

length = 18 ft

Step-by-step explanation:

Let w = width

L = w+7

Area = l*w

198 = (w+7) (w)

Distribute

198 = w^2 +7w

Subtract 198 from each side

0 = w^2 +7w -198

Factor

What 2 numbers multiply to -198 and add to 7

18* -11 = -198

18+-11 = 7

0=(w+18) (w-11)

Using the zero product property

w+18 =0  w-11=0

w= -18   w=11

We cannot have negative width  so w=11

We want the length

l = w+7

l = 11+7 = 18

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3 years ago
6. How do you find the slope of a line?
S_A_V [24]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
I don't understand how to do this. Can someone help?
miskamm [114]
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15minutes+3minutes=18minutes
Time used for the call to London: ($7.25-$1.25)/$0.25=24 minutes
24minutes+3minutes=27minutes
Difference between the two calls:27-18=9minutes
3 0
4 years ago
Is the sequence 7, 9, 11, 13,.. A)arithmetic B)geometric C) both D)netheir
ladessa [460]
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6 0
3 years ago
Read 2 more answers
Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

5 0
3 years ago
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