3 years ago

4 이 0 11| -1 2 . -3 1 -3 -11

Mathematics

1 answer:

Agata [3.3K]3 years ago

3 0

Answer:

what are we answering?

Step-by-step explanation:

huh

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If x^2=4 then x=2 pleas help me

pochemuha

$x^2=4\Longrightarrow x=4^{2^{-1}}=4^{\frac{1}{2}}=\sqrt{4}=\boxed{2}$

So the first one is correct which implies that the third one is also correct.

But these are not the only ones.

$2x=2\Longrightarrow x=\dfrac{2}{2}=\boxed{1}$

The last one is also correct.

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Given f (x)=2x-5x-3 and g (x)=2x^2+x what is (f/g)(x)<br>

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ANSWER

$( \frac{f}{g} )(x ) = \frac{x - 3}{x} \: where \: \: x \ne0, - \frac{1}{2}$

EXPLANATION

Given:

$f(x) = 2 {x}^{2} - 5x - 3$

and

$g(x) = 2 {x}^{2} + x$

Then,

$( \frac{f}{g} )(x ) = \frac{f(x)}{g(x)}$

Substitute the given functions;

$( \frac{f}{g} )(x ) = \frac{2 {x}^{2} - 5x - 3}{2 {x}^{2} + x}$

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$( \frac{f}{g} )(x ) = \frac{2x(x - 3) +1 (x - 3)}{x(2x + 1)}$

$( \frac{f}{g} )(x ) = \frac{(2x + 1)(x - 3) }{x(2x + 1)}$

Cancel the common factors.

$( \frac{f}{g} )(x ) = \frac{x - 3}{x} \: where \: \: x \ne0, - \frac{1}{2}$

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