Using the normal distribution, it is found that the correct option is:
- P(Y< 16) = 0.041. About 4.1% of all toco toucans weigh less than 16 ounces
In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- Mean of 20 ounces, hence
.
- Standard deviation of 2.3 ounces, hence
P(Y < 16) is the <u>p-value of Z when X = 16</u>, hence:
has a p-value of 0.041.
This is valid for the entire population, hence, the correct interpretation is:
- P(Y< 16) = 0.041. About 4.1% of all toco toucans weigh less than 16 ounces
A similar problem is given at brainly.com/question/24663213
Answer:
146%
Step-by-step explanation:
To find the percent increase/decrease:
1. Subtract the original value from the new value.
2. Divide by the original value.
3. Multiply the decimal by 100 to convert to a percent.
98.9 - 40.2 = 58.7
58.7/40.2 = 1.46
1.46*100 = 146%
Answer:
225600
Step-by-step explanation:
Simple interest formula:
A = P(1 + rt)
A = final amount
P = initial principal balance
r = annual interest rate
t = time (in years)
So...
A = 600(1 +(75 x 5) )
75 x 5 = 375
1 + 375 = 376
600 x 376 = 225600
A = 225600
Answer: The .30 per mile is the independent, because it is manipulated, and changed throughout. DRY MIX : Dependent, Responding, Y axis. Manipulated, Independent, X axis.
To minimize the cost, we take the straight distance from the refinery to the other side of the river as 2 km. Also, the 7 km will be the distance that has to be traveled by the pipeline in land. The total cost, C, is therefore,
total cost = (2 km)($800,000/km) + (7 km)($400,000 /km)
total cost = $4,400,000
Thus, the total cost of the pipeline is approximately $4,400,000.00.
