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Sati [7]
3 years ago
8

A graph question help

Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

dont know sorry but i guess b or c

Step-by-step explanation:

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What equals 12.5 in multiplication
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2 x 6.25 
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WILL MARK BRAINLIEST!!!
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option D.

Step-by-step explanation:

average rate of change in steel production over the eight days=-0.15 tons per day

Step-by-step explanation:

The production rate of a steel factory is declining due to old machinery. Over the last eight days production has dropped by 1.2 tons.

Production is dropped by 1.2 tons, so its negative

Average rate of change = Change in production / number of days

Average rate of change = -1.2/ 8= -0.15

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2 years ago
Construct the discrete probability distribution for the random variable described. Express the probabilities as simplified fract
lisov135 [29]

Answer:

P(X = 0) = 0.03125

P(X = 1) = 0.15625

P(X = 2) = 0.3125

P(X = 3) = 0.3125

P(X = 4) = 0.15625

P(X = 5) = 0.03125

Step-by-step explanation:

For each toss, there are only two possible outcomes. Either it is tails, or it is not. The probability of a toss resulting in tails is independent of any other toss, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Fair coin:

Equally as likely to be heads or tails, so p = 0.5

5 tosses:

This means that n = 5

Probability distribution:

Probability of each outcome, so:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.5)^{0}.(0.5)^{5} = 0.03125

P(X = 1) = C_{5,1}.(0.5)^{1}.(0.5)^{4} = 0.15625

P(X = 2) = C_{5,2}.(0.5)^{2}.(0.5)^{3} = 0.3125

P(X = 3) = C_{5,3}.(0.5)^{3}.(0.5)^{2} = 0.3125

P(X = 4) = C_{5,4}.(0.5)^{4}.(0.5)^{1} = 0.15625

P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125

5 0
2 years ago
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