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3 years ago

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Select the correct answer from the drop-down menu. And the surface area of this triangular prism. 2 in. 10 in. 6 in. 2 in. 8 in.

The surface area of the shape is square inches. Reset Next

1 answer:

seraphim [82]3 years ago

6 0

Answer:

96

Step-by-step explanation:

i just did math and got it correct

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A basketball has a diameter of 10 in. Using = 3.14, what is the approximate volume of the basketball in cubic inches?

m_a_m_a [10]

Answer:

523.3 cubic inches

Step-by-step explanation:

A basketball has a diameter of 10 in. Using = 3.14, what is the approximate volume of the basketball in cubic inches?

The shape of a basketball is spherical.

Hence:

The volume of a basketball = 4/3 × π × r³

From the question,

π = 3.14

r = radius = Diameter/2

r = 10 in/2 = 5 in

Hence:

The volume of the basketball

= 4/3 × 3.14 × 5³

= 1570 ÷ 3

= 523.33333333 cubic inches

Therefore, the approximate volume of the basketball = 523.3 cubic inches

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3 years ago

How do you find The area of a composite shape

myrzilka [38]

Answer:

Step-by-step explanatiArea of Composite Shapes. Composite shapes are shapes that have a combination of 2-D shapes. To find the area of composite shapes you just need to break down the shape into individual pieces and calculate their separate pieces then add them back together again to find a total areaon:

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3 years ago

2.432 2.09 2.190 2.37 least to greatest

Rus_ich [418]

2.09, 2.190, 2.37, 2.432

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4 years ago

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3 years ago

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A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.

$h(t)=-48t -16t^2$

$h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2$

$h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})$

$h(-\frac{3}{2})=72-4*9$

$h(-\frac{3}{2})=72-36$

$h(-\frac{3}{2})=36$

Therefore, the maximum height of the ball is 36 feet.

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3 years ago