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nataly862011 [7]
3 years ago
9

Assume that process that makes the parts can be altered to adjust the overall mean of the reflectiveness score. Also assume that

if an individual part has a score less than 85, then the part is given a passing quality score. The adjusted value of the true mean in population S that would result in approximately 80% of parts from that population being given a passing score is:______
a. greater than 80
b. less than 80
c. equal to 80
Mathematics
1 answer:
Dvinal [7]3 years ago
6 0

Answer:

c. equal to 80

Step-by-step explanation:

Given that:

The population mean = 80

The standard deviation is = 6

The sample mean = 85

The objective is to find the probability that is less than 85

P(X < 85) = P( Z < \dfrac{x-\mu}{\sigma})

P(X < 85) = P( Z < \dfrac{85-80}{6})

P(X < 85) = P( Z < \dfrac{5}{6})

P(X < 85) = P( Z < 0.833)

From the standard normal table

P(X <85) = 0.7977

P(X< 85) = 79.77%

P(X< 85) = 80%

Therefore, The adjusted value of the true mean in population S that would result in approximately 80% of parts from that population being given a passing score is: <u>  equal to 80    .</u>

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