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2 years ago

4=2/7x please awnser

Mathematics

1 answer:

n200080 [17]2 years ago

3 0

4=2/7x
(7)4=2/7x(7)
28=2x
— —
2. 2
14=x

x=14

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Help me with 32 please!!!!!!

Alexeev081 [22]

-8x - 46 = -6x - 8
-8x + 6x = -8 + 46
-2x = 38
x = -19

The equation:
-8x - 46 = -6x - 8

The solution:
x = -19

8 0

3 years ago

Ethan pays 52.80 for some more f the boxes work out the number of boxes he buys 1 box 2.40 2 4.80 and 5 12 10 24

Slav-nsk [51]

The pricing of the boxes seems to be consistently 2.40 per box. Ethan's cost is
.. 52.80 = 2.40 * (# of boxes)
.. 52.80/2.40 = (# of boxes)
.. 22 = # of boxes

Ethan has bought 22 boxes for 52.80.

5 0

3 years ago

Consider the first three terms of the arithmetic sequence: 7, 15, 23,... Determine d, the common difference.

ValentinkaMS [17]

Answer:

I think 47 and 55

Explanation:

I think that each number is the previous one plus 8;

7+8=15

15+8=23

23+8=31

31+8=39

So, next will be:

39+8=47

47+8=55

Is this what ur looking for?? hope this help:)

3 0

2 years ago

What is the slope of the line with the equation y-3=-1/2(x-2)?

torisob [31]

Answer: $-\frac{1}{2}$

Step-by-step explanation:

$y -3 = -\frac{1}{2}(x-2)$

Write as slope-intercept form y = mx + b, where m is the slope and b is the y-intercept.

$y-3=-\frac{1}{2}x + 1$

$y = -\frac{1}{2}x+4$

Therefore, the slope is $-\frac{1}{2}$ .

8 0

1 year ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago