Answer:
the answer is y=1x+(-1) or just 1x-1
Step-by-step explanation:
(f-g)(x) = x^2 - 3x + 2
If f(x) = x^2+ 1 and g(x) = 3x-1
Then (f-g)(x) = (x^2+ 1 )(-(3x-1)
(f-g)(x) = x^2 + 1 - 3x + 1
-64
Hope it helps