Can you guys help me out pls

Mathematics

1 answer:

kozerog [31]3 years ago

8 0

Answer is for sure b

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2 ≤ q–1 = ???????????????????????????

crimeas [40]

Answer:

q ≥ 3

Step-by-step explanation:

add 1 to both sides and there you have your answer!

2 ≤ q-1

+1 +1

3 ≤ q

q ≥ 3

5 0

3 years ago

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There are fifteen teams in a high school baseball league. How many different orders of finish are possible for the first four p

ankoles [38]

There are 32,760 different orders for the first four positions.

This is a permutation where repetition is not allowed; the formula for that is:

$_nP_r=\frac{n!}{(n-r)!}$

For our problem, we have:
$_{15}P_4=\frac{15!}{(15-4)!}=\frac{15!}{11!}=32760$

3 0

3 years ago

Please Help. 25 points. <br>

vodomira [7]

Answer:

$\boxed{x = 7, y = 9, z = 68}$

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

$\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}$

$\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}$