Can someone please do this for me

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

7 0

Next time please indicate which problem you want to work on.

One example of an equation with variables present on both sides is

y-b = m(x-a). Given the slope of a line and one point (a,b) through which the line passes, you can come up with an equation of the line.

Or, given the numeric value of y-b and that of x-a, you could obtain the slope of the line thru the points (x,y) and (a,b).

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Last year, a farmer harvested 3 tons of strawberries. This year, the harvest was 20% more. How many tons of strawberries did the

MariettaO [177]

Answer:

3.6 I think

Step-by-step explanation:

Times 3 by 1.2 im sorry if I was wrong.

7 0

3 years ago

Factor of −21x^2+2x+8

Vanyuwa [196]

Answer:

-(7x + 4)(3x - 2)

Step-by-step explanation:

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5 0

3 years ago

The measures of a triangle are in the ratio 2:3:5. what are the measures of the angles?

xxTIMURxx [149]

9514 1404 393

Answer:

36°, 54°, 90°

Step-by-step explanation:

We have to assume that the given measures are angle ratios, not side ratios. Sides in the ratios 2:3:5 will not form a triangle.

For some multiplier x, the angle values will total 180°.

2x +3x +5x = 180

x = 180/(2+3+5) = 18

Then the angle measures are ...

2x° = 2·18° = 36°

3x° = 3·18° = 54°

5x° = 5·18° = 90°

The angle measures are 36°, 54°, and 90°.

6 0

3 years ago

Read 2 more answers

What's the area of this yellow surface? pick one of the options.

Oksi-84 [34.3K]

28 in^2

Divide shape into one rectangle and two squares:

Area of rectangle:
10 x 2 = 20 in^2

Area of one square:
2 x 2 = 4 in^2

Multiply that by 2 because we have 2 squares similar in size:
4 in^2 x 2 = 8 in^2

Add the area of the rectangle and two squares:
20 in^2 + 8 in^2 = 28 in^2

Have a nice day
Hope this helps!

4 0

3 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .