3 years ago

Given f(x)=2/5(6-x)^2 what is the value of f(6)?

Mathematics

1 answer:

bulgar [2K]3 years ago

5 0

Answer:

Step-by-step explanation:

f(x) = 2/5(6 - x)²

f(6) = 2/5[6 - (6)]²

f(6) = 2/5(0)²

f(6) = 0

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Given f(x)=2/5(6-x)^2 what is the value of f(6)?​

Given f(x)=2/5(6-x)^2 what is the value of f(6)?