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Art [367]
3 years ago
10

Given f(x)=2/5(6-x)^2 what is the value of f(6)?​

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

0

Step-by-step explanation:

f(x) = 2/5(6 - x)²

f(6) = 2/5[6 - (6)]²

f(6) = 2/5(0)²

f(6) = 0

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