Evaluate the expression for a^2 + b ÷3 when a = 3 and b = 6
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Equation of a circle is (x-x1)+(y-y1)=r²
when x1 and y1 are the coordinates of the centre
So you can substitute the centre in to get (x-5)²+(y+9)²=r²
When you draw a diagram it's obvious the radius is 9
9²=81
Therefore equation is (x-5)²+(y+9)²=81
Any questions, just ask :)
when x1 and y1 are the coordinates of the centre
So you can substitute the centre in to get (x-5)²+(y+9)²=r²
When you draw a diagram it's obvious the radius is 9
9²=81
Therefore equation is (x-5)²+(y+9)²=81
Any questions, just ask :)
