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nirvana33 [79]
2 years ago
5

1" title="\int _{2.2}^{+\infty \:}\frac{10.648}{x^2}" alt="\int _{2.2}^{+\infty \:}\frac{10.648}{x^2}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Rus_ich [418]2 years ago
5 0

Step-by-step explanation:

\int _{2.2}^{+\infty \:}\frac{10.648}{x^2}dx = 10.648 \int _{2.2}^{\infty \:}\frac{dx}{x^2}

=  -  \frac{10.648}{x} | _{2.2}^{ \infty}  = 4.84

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