<img src="https://tex.z-dn.net/?f=%5Cint%20_%7B2.2%7D%5E%7B%2B%5Cinfty%20%5C%3A%7D%5Cfrac%7B10.648%7D%7Bx%5E2%7D" id="TexFormula

All categories

1 year ago

1" title="\int _{2.2}^{+\infty \:}\frac{10.648}{x^2}" alt="\int _{2.2}^{+\infty \:}\frac{10.648}{x^2}" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Rus_ich [418]1 year ago

5 0

Step-by-step explanation:

$\int _{2.2}^{+\infty \:}\frac{10.648}{x^2}dx = 10.648 \int _{2.2}^{\infty \:}\frac{dx}{x^2}$

$= - \frac{10.648}{x} | _{2.2}^{ \infty} = 4.84$

You might be interested in

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately 923.558 m²

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ 923.558 m²

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

2 years ago

Cuál es el resultado de la siguiente adicion? 3/4 + (- 2/5) +(6/3) =

SCORPION-xisa [38]

Answer:47/20 or 2.35 in decimal form

Step-by-step explanation:

7 0

2 years ago

The medium in which a story is presented most affects the

katen-ka-za [31]

Answer:

audience's perspective of a story - please give brainliest

6 0

2 years ago

In the diagram of circle O, what is the measure of ? 27° 54° 108° 120°

vesna_86 [32]

Answer:

Option (2).

Step-by-step explanation:

This question is incomplete; here is the complete question and find the figure attached.

In the diagram of a circle O, what is the measure of ∠ABC?

27°

54°

108°

120°

m(minor arc $\widehat {AC}$ ) = 126°

m(major arc $\widehat {AC}$ ) = 234°

By the intersecting tangents theorem,

If the two tangents of a circle intersect each other outside the circle, measure of angle formed between them is half the difference of the measures of the intercepted arcs.

m∠ABC = $\frac{1}{2}[m(\text {major arc{AC})}-m(\text{minor arc} {AC})]$

= $\frac{1}{2}(234-126)$

= 54°

Therefore, Option (2) will be the answer.

6 0

2 years ago

Read 2 more answers

4-2x=11 how do I solve

Bingel [31]

Hey there!☺

$Answer:\boxed{x=\frac{-7}{2}}$

$Explanation:$

$4-2x=11$

In our first step, we will simplify both sides of the equation:

$4+-2x=11\\-2x+4=11$

Now subtract 4 from both sides:

$-2x+4-4=11-4\\-2x=7$

In our last step, we will divide both sides by -2:

$\frac{-2x}{2}=\frac{7}{-2}\\ x=\frac{-7}{2}$

x=-7/2 is your answer.

Hope this helps!☺

3 0

2 years ago