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3 years ago

What is the order of the numbers from least to greatest?

Mathematics

2 answers:

Mariana [72]3 years ago

8 0

Answer:

-2 3/4, -2, -1 1/2, -0.8, -1/3, 0.2

Step-by-step explanation:

The bigger the negitive, the smaller the number, it's the opposite for the positives

Marina86 [1]3 years ago

3 0

-2 3/4, -2, -1 1/2, -0.8, -1/3, 0.2

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Can anybody help me please

klio [65]

Answer:

x y

0 -1

-1 0

-8 7

Step-by-step explanation:

y = -x - 1

when x = 0, y = -1

when y = 0

0 = -x - 1

x = -1

when x = -8,

y = -(-8) - 1

y = 7

8 0

3 years ago

Read 2 more answers

Please help me :(? I will mark BRAINLIST!

fgiga [73]

Answer:

1.) B

2.) B

Step-by-step explanation:

Number 1 is B bc rapid population in Mexico is caused by the economy improving.

Number 2 is B bc if there was one political party , there would be little opposition in the government. It basically means disaster.

7 0

3 years ago

The number of 8th graders in choir is three times the number of the 7th graders. if there are 48 8th graders choir how.many 7th

stira [4]

Divide 48 by 3, for every three 8th graders, there is one 7th grader in choir
48÷3=16
There's 16 7th graders in choir !!

7 0

3 years ago

Leah and 15 of her friends want to share 11 cookies equally. What decimal is equivalent to the fraction of a cookie each will ge

mote1985 [20]

Answer:

0.688

Step-by-step explanation:

There are 16 people total and 11 cookies.

This can be represented as:

$\frac{16}{11}$ ,

which converted into a decimal is:

0.688

8 0

2 years ago

An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

$P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107$

Then,

$P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007$

c) In this case, the distribution is B(1200,0.01)

$P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924$

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

$P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366$

5 0

3 years ago