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Firlakuza [10]
3 years ago
15

I do not have the facilities to do this question

Mathematics
1 answer:
emmainna [20.7K]3 years ago
5 0

Answer:

12

Step-by-step explanation:

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A________ has cross-sectional shapes, taken parallel to a base, that are similar
alexdok [17]

Answer:

I think it is C

Step-by-step explanation

<em>cube has equal sides and is parallel.</em>

3 0
2 years ago
Test the series for convergence or divergence (using ratio test)​
Triss [41]

Answer:

    \lim_{n \to \infty} U_n =0

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given series is an alternating series

∑(-1)^{n} \frac{n^{2} }{n^{3}+3 }

Let   U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }

By using Leibnitz's rule

   U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }

 U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}

Uₙ-Uₙ₋₁ <0

<u><em>Step(ii):-</em></u>

    \lim_{n \to \infty} U_n =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }

                       =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }

                    = =  \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }

                       =\frac{1}{infinite }

                     =0

    \lim_{n \to \infty} U_n =0

∴ Given series is converges

                       

                     

 

3 0
3 years ago
$70 with a 25% discount
stealth61 [152]
70(.25) = 17.25
70 - 17.25 = 52.50
3 0
2 years ago
Divide. Write your answer in simplest form.<br> 7<br> -:6<br> 3
NikAS [45]

Answer:

7/2

Step-by-step explanation:

rewrite the equation

7 / 6 / 3

7 /2

simplest doesn't mean answer fully just get to the simplest form where there are only absolute numbers

5 0
3 years ago
Hey answer equation please thanks
Ainat [17]

Answer:

30 y

Step-by-step explanation:

We need to multiply 5 by 4y and 5 by 2 y

20y + 10y = 30y

6 0
3 years ago
Read 2 more answers
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