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Firlakuza [10]
3 years ago
15

I do not have the facilities to do this question

Mathematics
1 answer:
emmainna [20.7K]3 years ago
5 0

Answer:

12

Step-by-step explanation:

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How many solutions are there to each of these equations?
Sloan [31]

Answer:

first one, put value of x= -3 and y = 0

second one, pit vale of x=7 and y= -7

Step-by-step explanation:

first one,

-14(-3) -20(0) =42

or, 42-0 = 42

or, 42 = 42

proved

second one,

-14(7) -20(-7) = 42

or, -98 + 140=42

or, 42 = 42

proved

6 0
3 years ago
If the mean of 4,6,4,7,(x+1),8 and 2 is 5 ,find the median​
Rainbow [258]
<h3>Answer:  Median = 4</h3>

===========================================================

Explanation:

The mean is found by adding up all of the values and dividing by n, where n is the number of values in the set.

In this case, we have n = 7 values here. We count (x+1) as well since x is a placeholder for a number, which makes (x+1) also a placeholder in a sense.

As for what replaces x, we're not sure yet but we can use algebra to solve.

Lets add up all of the values given except for the "5" at the end. That 5 is the mean which is not part of the data set.

Adding up those values mentioned gives:

4+6+4+7+(x+1)+8+2 = x+32

Then divide this over n = 7 to get the mean 5

(x+32)/n = mean

(x+32)/7 = 5

-----------------------------

Let's isolate x

(x+32)/7 = 5

x+32 = 7*5

x+32 = 35

x = 35-32

x = 3

If x = 3, then x+1 = 3+1 = 4

So the (x+1) is being a placeholder for the number 4.

In other words, we'll replace the (x+1) with 4.

The data set of

4,6,4,7,(x+1),8,2

updates to

4,6,4,7,4,8,2

-----------------------------

We'll get to the median in a moment, but first we need to check if we have the correct replacement for (x+1)

Add up the values in the set {4,6,4,7,4,8,2}

Doing so leads to: 4+6+4+7+4+8+2 = 35

Then divide by n = 7 to compute the mean: 35/n = 35/7 = 5

We get the mean is 5 which matches with the instructions. So we have the correct replacement for the (x+1). We can now find the median.

------------------------------

To find the median of any data set, we need to make sure the numbers are in order from smallest to largest.

Right now {4,6,4,7,4,8,2} is not sorted, but we can sort the items to get {2,4,4,4,6,7,8}

The median is at the exact middle. In this set, the median is that third copy of '4'. Note how "2,4,4" is to the left of the median while "6,7,8" is to the right of the median. There is the same number of values on either side of the median to show things are balanced and we are at the center point.

As an alternative, you can cross off each pair of outer values one at a time until you steadily arrive at the midpoint, which again is that third copy of '4'.

So that's why the median is 4.

8 0
3 years ago
Pork chops cost $3.30 a pound at the market. Mary buys 4.4 pounds. Find the cost. a. $7.70 b. $14.52 c. $18.92 d. $15.52
Fofino [41]

Answer:

B) $14.52

Step-by-step explanation:

1 lb of pork chop = $3.30

Mary is buying 4.4 pounds.

Multiply 4.4 with 3.30

4.4 x 3.30 = 14.52

$14.52, or B) is your answer

~

8 0
3 years ago
Read 2 more answers
50 points
mixer [17]

Answer:

c = -13.78.

Step-by-step explanation:

21.2x + c  ≡ 5.3(4x - 2.6)

21.2x + c  ≡ 21.2x - 13.78

Equating constant terms:

c = -13.78.

7 0
2 years ago
Read 2 more answers
The graph below shows two polynomial functions, f(x) and g(x):
neonofarm [45]
The answer is '<span>f(x) is an odd degree polynomial with a positive leading coefficient'.

An odd degree polynomial with a positive leading coefficient will have the graph go towards negative infinity as x goes towards negative infinity, and go towards infinity as x goes towards infinity.

An even degree polynomial with a negative leading coefficient will have the graph go towards infinity as x goes toward negative infinity, and go towards negative infinity as x goes toward infinity.

g(x) would have a a positive leading coefficient with an even degree, as the graph goes towards infinity as x goes towards either negative or positive infinity.
</span>
3 0
4 years ago
Read 2 more answers
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