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nordsb [41]
3 years ago
8

An inequality is given. √a < √50 < √b The variables a and b are consecutive perfect squares. What are the values of a and

b?​
Mathematics
1 answer:
Naya [18.7K]3 years ago
6 0

Given:

The inequality is

\sqrt{a}         ...(i)

The variables a and b are consecutive perfect squares.

To find:

The values of a and b.

Solution:

We know that, perfect square of natural numbers are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, ...

Clearly, 50 lines between two consecutive perfect square 49 and 64.

49

\sqrt{49}        ...(ii)

On comparing (i) and (ii), we get

a=49,b=64

Therefore, the values of a and b are 49 and 64 respectively.

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you are given numbers, {30 + n, n/3, square root n+16}. Find the smallest value of n so that all of the numbers in the set are n
Juli2301 [7.4K]
<h3>Answer:   n = 9</h3>

========================================================

Explanation:

Let's assume that n is not negative. If we tried the smallest nonnegative value, n = 0, then we get

  • 30+n = 30+0 = 30
  • n/3 = 0/3 = 0
  • sqrt(n+16) = sqrt(0+16) = 4

The middle result 0 isn't a natural number. The set of natural numbers is {1,2,3,4,...} which is the set of positive whole numbers.

So we can't use n = 0.

Through trial and error, you should find that n = 9 is the next value we can try such that sqrt(n+16) is a natural number, and so is n/3.

If n = 9, then,

  • 30+n = 30+9 = 39
  • n/3 = 9/3 = 3
  • sqrt(n+16) = sqrt(9+16) = 5

We see that the middle result is now larger than 0 and it's a natural number. The same can be said for the last result as well.

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3 years ago
Help please! 24 = - y/7​
liq [111]

Answer:

-y/7 = 24

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Step-by-step explanation:

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tankabanditka [31]

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