Question

PLZ HELP DUE SOOOONNNN (solve for z).

Answer 1

Answer:

${\huge{\green{\mathsf{z\:=\sqrt{\frac{4x}{3y}}}}}$

Step-by-step explanation:

Given the algebraic equation, ${\huge{\green{\mathsf{x\:=\frac{3yz^2}{4}}}}$, and that we must solve for z :

The first step is to multiply both sides by 4 to eliminate the fraction on the right-hand side of the equation:

${\huge{\green{\mathsf{x\:=\frac{3yz^2}{4}}}}$

${\huge{\green{\mathsf{(4)\:x\:=\frac{3yz^2}{4}(4)}}}$

4x = 3yz²

Next, divide both sides by 3y:

${\huge{\green{\mathsf{\frac{4x}{3y}\:=\frac{3yz^2}{3y}}}}$

${\huge{\green{\mathsf{\frac{4x}{3y}\:=z^2}}}$

Lastly, take the square root of both sides to isolate the variable, z :

${\huge{\green{\mathsf{\sqrt{\frac{4x}{3y}}\:=\sqrt{z^2}}}}$

${\huge{\green{\mathsf{z\:=\sqrt{\frac{4x}{3y}}}}}$

Therefore, the equation for z is:   ${\huge{\green{\mathsf{z\:=\sqrt{\frac{4x}{3y}}}}}$

Answer 2

Please find attached photograph for your answer.

Hope it helps.

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