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3 years ago

Select all of the sentences that are punctuated correctly.

Mathematics

2 answers:

STatiana [176]3 years ago

6 0

The dog's bowl was empty.

The singer's songs were finished.

Viktor [21]3 years ago

6 0

Answer:

The dogs's bowl was empty. This is wrong as there dogs's is not the way to write.

The dog's bowl was empty. This is the correct form where dog's is written properly.

The singers's songs were finished. This is wrong as singers's is not the way to write.

The singers' songs were finished. This is also correct as singer's is written properly.

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Samantha wants to know whether the food she serves in her restaurant is within a safe range of

nikitadnepr [17]

Answer: The population would be the data of temperatures of all food served by the restaurant.

Step-by-step explanation:

In a statistical study, the term population refers to the largest group of all individuals related to the study or the objective of the study.

Here, the objective of the study= To check the temperatures of food just before serving.

Population = Data of temperatures of all dishes served by restaurant.

Hence, the population would be the data of temperatures of all dishes served by the restaurant.

5 0

2 years ago

What is the solution to the linear equation? –12 + 3b – 1 = –5 – b

marysya [2.9K]

-12+3b-1=-5-b
Combine like terms to get:
3b-13=-5-b
Add 13 to both sides:
3b= 8-b
Add b to both sides:
4b=8
Divide both sides by 4:
4b/4=8/4
b=2

Final answer
b=2

4 0

3 years ago

Read 2 more answers

HELP PLEASE!!! Ashton drew a triangle with vertices A (-1,2), B (5,2) and C (5.-1). He then rotated the triangle 180°

Naddika [18.5K]

Answer: The rule is when rotating 90 degrees, it's (-y, x), 180 degrees is (-x, -y), and 360 degrees is (y, -x). Just plug in the numbers accordingly, and you should get the correct answer. It worked for me <3.

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3 years ago

Solve each equation for xx. For each step, describe the operation used to convert the equation. How do you know that the initial

ladessa [460]

Answer:

a. x=1.8?

Step-by-step explanation:

im not really sure but i need help also. Im sorry but i just thought to say something.

4 0

3 years ago

Consider the three points ( 1 , 3 ) , ( 2 , 3 ) and ( 3 , 6 ) . Let ¯ x be the average x-coordinate of these points, and let ¯ y

loris [4]

Answer:

$m=\dfrac{3}{2}$

Step-by-step explanation:

Given points are: ( 1 , 3 ) , ( 2 , 3 ) and ( 3 , 6 )

The average of x-coordinate will be:

$\overline{x} = \dfrac{x_1+x_2+x_3}{\text{number of points}}$

1) Finding $(\overline{x},\overline{y})$

Average of the x coordinates:

$\overline{x} = \dfrac{1+2+3}{3}$

$\overline{x} = 2$

Average of the y coordinates:

similarly for y

$\overline{y} = \dfrac{3+3+6}{3}$

$\overline{y} = 4$

2) Finding the line through $(\overline{x},\overline{y})$ with slope m.

Given a point and a slope, the equation of a line can be found using:

$(y-y_1)=m(x-x_1)$

in our case this will be

$(y-\overline{y})=m(x-\overline{x})$

$(y-4)=m(x-2)$

$y=mx-2m+4$

this is our equation of the line!

3) Find the squared vertical distances between this line and the three points.

So what we up till now is a line, and three points. We need to find how much further away (only in the y direction) each point is from the line.

Distance from point (1,3)

We know that when x=1, y=3 for the point. But we need to find what does y equal when x=1 for the line?

we'll go back to our equation of the line and use x=1.

$y=m(1)-2m+4$

$y=-m+4$

now we know the two points at x=1: (1,3) and (1,-m+4)

to find the vertical distance we'll subtract the y-coordinates of each point.

$d_1=3-(-m+4)$

$d_1=m-1$

finally, as asked, we'll square the distance

$(d_1)^2=(m-1)^2$

Distance from point (2,3)

we'll do the same as above here:

$y=m(2)-2m+4$

$y=4$

vertical distance between the two points: (2,3) and (2,4)

$d_2=3-4$

$d_2=-1$

squaring:

$(d_2)^2=1$

Distance from point (3,6)

$y=m(3)-2m+4$

$y=m+4$

vertical distance between the two points: (3,6) and (3,m+4)

$d_3=6-(m+4)$

$d_3=2-m$

squaring:

$(d_3)^2=(2-m)^2$

3) Add up all the squared distances, we'll call this value R.

$R=(d_1)^2+(d_2)^2+(d_3)^2$

$R=(m-1)^2+4+(2-m)^2$

4) Find the value of m that makes R minimum.

Looking at the equation above, we can tell that R is a function of m:

$R(m)=(m-1)^2+4+(2-m)^2$

you can simplify this if you want to. What we're most concerned with is to find the minimum value of R at some value of m. To do that we'll need to derivate R with respect to m. (this is similar to finding the stationary point of a curve)

$\dfrac{d}{dm}\left(R(m)\right)=\dfrac{d}{dm}\left((m-1)^2+4+(2-m)^2\right)$