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horsena [70]
3 years ago
11

8. Lauren wants to buy a shirt that costs $80. Her mother told her that she could only spend $35 for the shirt. The shirt finall

y went on sale for 40% off the original price. Will Lauren be able to buy the shirt? (Hint: If the shirt is 40% off the original price, what percent is she paying?)
Mathematics
1 answer:
Artist 52 [7]3 years ago
4 0

Answer:

No. Lauren cannot buy the shirt. It costs $48 after the discount.

Step-by-step explanation:

Shirt Cost: $80

Money: $35

Discount: 40%

First, find the amount of the discount by finding 40% of the price. 40% is equal to 0.40 (or 40 divided by 100).

40% of $80 = 0.40 x 80 = $32

Since it's a discount, the final price is the original price minus the discount.

$80 - $32 = $48

So, after a 40% discount, the price is still $48. Lauren only has $35, so it will still be too expensive!

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Aloiza [94]
\dfrac{x}{x+1} \ , \  \dfrac{7x}{x-1}

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<u>We know that (a + b)(a - b) = a² - b²:</u>

\dfrac{x (x -1)}{x^2 - 1}} \ , \ \dfrac{7x(x+1)} {x^2 - 1}

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8 0
3 years ago
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If you add the digits in a two-digit number and multiply the sum by 7, you get the original number. If you reverse the digits in
kolbaska11 [484]
The answer is A. 42

Solution:
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simplifying:
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3 0
3 years ago
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Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

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We find the critical points equating f'(x) to zero

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Simplifying by -6

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We get the critical points

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They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

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Anything above zero would be the right answer, since there is an asymptote at y=0.

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