Answer:
The probability that there are 3 or less errors in 100 pages is 0.648.
Step-by-step explanation:
In the information supplied in the question it is mentioned that the errors in a textbook follow a Poisson distribution.
For the given Poisson distribution the mean is p = 0.03 errors per page.
We have to find the probability that there are three or less errors in n = 100 pages.
Let us denote the number of errors in the book by the variable x.
Since there are on an average 0.03 errors per page we can say that
the expected value is, 
= E(x)
= n × p
= 100 × 0.03
= 3
Therefore the we find the probability that there are 3 or less errors on the page as
P( X ≤ 3) = P(X = 0) + P(X = 1) + P(X=2) + P(X=3)
Using the formula for Poisson distribution for P(x = X ) = 
Therefore P( X ≤ 3) = 
= 0.05 + 0.15 + 0.224 + 0.224
= 0.648
The probability that there are 3 or less errors in 100 pages is 0.648.
this question is incorrect because the decimal quantity functional persistent shouldnt be in a sequential farfictional order so the answer would be that satisfactory angle of theslop devided by pi and then multiplied by the persistent. hope this helped!
Answer:
coordinate points
Step-by-step explanation:
variables: a symbol for a value we don't know yet. ex: x or y
numbers: I hope you know what they are cuz i dunno how to describe it ex: 2
coordinate points: a set of numbers that show position on a graph ex: (2,4)
operations: adding, subtracting, multiplying, dividing
So,
To find the percentage that the copper comprises, just divide the amount of copper by the total amount of metal in the coin. In this case, we will change the denominator so that it is 100, which can easily be converted into a percentage, which is really just a fraction out of 100.
75%
75% of the metal in the coin is copper.
Answer:
74-25 is 49
Step-by-step explanation:
