Somebody help me pleaseeeeeeeeee
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Answer:
Probability Mass Function:
x: 0 1 2 3
P(x): 0.000064 0.004608 0.115902 0.884736
Step-by-step explanation:
We are given the following information:
We treat correct classification as a success.
P(correct classification) = 0.96
Then the number of classification follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 3 and x = 0, 1, 2, 3
We have to evaluate:
PMF:
x: 0 1 2 3
P(x): 0.000064 0.004608 0.115902 0.884736