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2 years ago

Help me with this please

Mathematics

1 answer:

bulgar [2K]2 years ago

5 0

$\huge \color{Lime} Answer:$

$\medium \color{Red} Cone$

$\medium \color{Yellow} Cylinder$

$\medium \color{Purple} Rectangular Prism$

$\medium \color{Green} Triangular Prism$

$\medium \color{Blue} Rectangular Pyramid$

<h2>Watch carefully because Cylinder and Rectangular Prism changed position.</h2>

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A sample of students is taken from the school's A honor roll. The school estimates that there are actually 360 students on the A

aliya0001 [1]

Answer:

360 - Y

Step-by-step explanation:

From the information provided in the question, we will understand that the question lacks detailed information.

Given that:

The total number of actual students on the A honor roll = 360

To find the number of students on the A honor roll of 8th graders;

Let denote Y to represent the total number of students who exist on the A honor roll except for the 8th graders.

Then:

The number of 8th graders = all number of students on are on the A honor roll - Y

The number of 8th graders = 360 - Y

If Y is known, then the number of the 8th graders can be fully determined.

5 0

2 years ago

In a basketball game 15 of 20 foul shots that Michelle attempted were successful. What percent of her shots were not successful?

mestny [16]

<u>Work 1:</u>
Successful Percent:
15 divided by 20 equals .75
.75 times 100 is equal to 75
75%
Not successful Percent:
100% minus 75% equals 25%
<em>25%</em>
<u>Work 2:</u><u />
20 minus 15 equals 5
5 divided by 20 is equal to .25
.25 times 100 is equal to 25
<em>25%</em>

7 0

2 years ago

Shari bought 3 breath mints and received $2.76 change.Jamal bought 5 breath mints and received $1.20 change. If Shari and Jamal

vekshin1

Answer:

Step-by-step explanation:

8 0

1 year ago

Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m

Dovator [93]

Option a: $\frac{m^{5} }{162n}$ is the equivalent expression.

Explanation:

The expression is $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ where $m\neq 0, n\neq 0$

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

$\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }$

Cancelling the like terms, we have,

$\frac{3^{-3}m^{5} n^{-1}}{6 }$

This equation can also be written as,

$\frac{m^{5}}{3^{3}6 n^{1} }$

Multiplying the terms in denominator, we have,

$\frac{m^{5} }{162n}$

Thus, the expression which is equivalent to $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ is $\frac{m^{5} }{162n}$

Hence, Option a is the correct answer.

8 0

2 years ago

Read 2 more answers

single die is rolled twice. Find the probability of rolling an oddodd number the first time and a number greater than 33 the sec

givi [52]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

A single die is rolled twice, we have to find the probability of rolling an odd number in first throw and a number greater than 3 in the second throw.

a) Rolling an Odd number in first throw

A die has total 6 possible outcomes, out of which 3 are odd numbers i.e. 1,3 and 5

So, total number of possible outcomes = 6

Total Favorable outcomes (Odd numbers) = 3

Probability is defined as the ratio of favorable outcomes to total number of outcomes. So,

The probability of rolling an odd number would be = $\frac{3}{6} = \frac{1}{2}$

b) Rolling a number greater than 3 in second throw

Here again total possible outcomes = 6

Favorable outcomes (Numbers greater than 3 are 4, 5 and 6) = 3

So,

The probability of rolling a number greater than 3 = $\frac{3}{6} = \frac{1}{2}$

These two events(rolls) are independent of each other, so the overall probability of both events occurring would be the product of individual probabilities.

So,

Probability of rolling an odd number the first time and a number greater than 3 the second time = $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

6 0

2 years ago