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3 years ago

Help me with this please

Mathematics

1 answer:

bulgar [2K]3 years ago

5 0

$\huge \color{Lime} Answer:$

$\medium \color{Red} Cone$

$\medium \color{Yellow} Cylinder$

$\medium \color{Purple} Rectangular Prism$

$\medium \color{Green} Triangular Prism$

$\medium \color{Blue} Rectangular Pyramid$

<h2>Watch carefully because Cylinder and Rectangular Prism changed position.</h2>

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Can you help me to solve this<br>

RUDIKE [14]

Answer:

Is the question even complete ?

Step-by-step explanation:

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2 years ago

Classify ABC by its sides. Then determine whether it is a right triangle.

m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

$AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

AB = $\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}$

Given vertices are B(6,9) and C( 6,-3)

$B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

= $\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12$

BC = 12

Given vertices are A(3,3) and C( 6,-3)

$AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}$

AC² = AB²+BC²

45 = 45+144

45 ≠ 189

∴Given Δ ABC is not a right angle triangle

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