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mestny [16]
3 years ago
7

WILL MARK YOU BRAINLIEST

Mathematics
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

parallelogram

Step-by-step explanation:

.........

SSSSS [86.1K]3 years ago
4 0

Answer:

i believe that is a parallelogram

Step-by-step explanation:

hope this helps :) have a nice day !! please let me know if that was wrong

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Find the amount to be paid at the end of 3years in each case. a) principal =1,200 at12% p.a​
Viktor [21]

Answer:

$1632

Step-by-step explanation:

Given data

Principal= $1200

Rate= 12%

Time= 3 years

The simple interest expression is given as

A= P(1+rt)

substitute

A=1200(1+0.12*3)

A=1200(1+0.36)

A=1200*1.36

A=$1632

Hence the amount is $1632

4 0
3 years ago
A recipe that makes 8 servings calls for 3/5 cup of flour. Jeff modifies the recipe so that it can serve 10. How many cups of fl
Blababa [14]
8 goes with 3/5: 10 goes with n     (n being the number of cups)

\frac{8}{3/5}  =  \frac{10}{n}

Use cross products and we get  8n = 6
Now divide by 8
<u>8n</u>  = <u>6
</u><u />8       8

n= 6/8 or 3/4 of a cup of flour.
8 0
3 years ago
What is the value of x when y equals 2 in the equation y equals x over 4 - 7
Alex

The value of x when y = 2 is x = 36

Step-by-step explanation:

The equation that we have in this problem is:

y=\frac{x}{4}-7

In order to find the value of x when y is equal to

y = 2

We need to re-arrange the equation making x the subject.

We proceed as follows:

1) We add +7 on both sides:

y+7=\frac{x}{4}-7+7\\y+7=\frac{x}{4}

2) Now we multiply both  sides by 4:

4(y+7)=\frac{x}{4}\cdot 4\\x=4(y+7)

3) Now we can substitute y = 2 and find the value of x:

x=4(2+7)=4(9)=36

Learn more about equations:

brainly.com/question/13168205

brainly.com/question/3739260

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5 0
3 years ago
The graph below shows the function f(x)=x-3/x2-2x-3. Which statement is true?
BARSIC [14]
1. Domain.

We have x^2-2x-3 in the denominator, so:

x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\&#10;(x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}

So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.

2. Asymptotes:

f(x)=\dfrac{x-3}{x^2-2x-3}=\dfrac{x-3}{(x-3)(x+1)}=\boxed{\dfrac{1}{x+1}}

We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
6 0
3 years ago
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