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gogolik [260]
3 years ago
11

​At a college, the cost of tuition increased by 10%. Let b represent the former cost of tuition. Use the expression b+0.10b for

the new cost of tuition.
Mathematics
1 answer:
kirza4 [7]3 years ago
4 0

Question is Incomplete,Complete question is given below;

At a college, the cost of tuition increased by 10%. Let b be the former cost of tuition. Use the expression b + 0.10b for the new cost of tuition.

a)  Write an equivalent expression by combining like terms.

b)  What does your equivalent expression tell you about how to find the new cost of tuition?

Answer:

a. The equivalent expression is 1.1b.

b. The new cost of tuition is 1.1 times the former cost of tuition.

Step-by-step explanation:

Given:

Former cost of tuition = b

the cost of tuition increased by 10%.

New cost of tuition = b+0.10b

Solving for part a.

we need to find the equivalent expression by combining the like terms we get;

Now Combining the like terms we get;

new cost of tuition = b(1+0.1) = 1.1b

Hence The equivalent expression is 1.1b.

Solving for part b.

we need to to say about equivalent expression about how to find the new cost of tuition.

Solution:

new cost of tuition = 1.1b

So we can say that.

The new cost of tuition is 1.1 times the former cost of tuition.

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B= 25°

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2 years ago
3. You want to have $4000 in your savings account after 2 years. Find the amount you should deposit for each of the situations d
pychu [463]

Answer:

Part A)

About $3767.34.

Part B)

About $3692.47.

Step-by-step explanation:

Part A)

Recall that compound interest is given by the formula:
\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}

Where <em>A</em> is the final amount, <em>P</em> is the initial amount, <em>r</em> is the interest rate, <em>n</em> is the number of times compounded per year, and <em>t</em> is the number of years.

To obtain $4000 after two years, let <em>A</em> = 4000 and<em> t</em> = 2.

Because the account pays 3% interest compounded monthly, <em>r</em> = 0.03 and <em>n</em> = 12.

Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned} (4000) & = P\left(1+\frac{(0.03)}{(12)}\right)^{(12)(2)} \\ \\ P & = \frac{4000}{\left(1+\dfrac{(0.03)}{(12)}\right)^{(12)(2)}} \\ \\ & \approx \$3767.34\end{aligned}

In concluion, about $3767.34 should be deposited.

Part B)

Recall the formula for continuous compound:

\displaystyle A = Pe^{rt}

Where <em>e</em> is Euler's number.

Hence, let <em>A</em> = 4000, <em>r</em> = 0.04 and <em>t</em> = 2. Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned}(4000) & = Pe^{(0.04)(2)} \\ \\ P & = \frac{4000}{e^{(0.02)(4)}} \\ \\ & \approx \$3692.47 \end{aligned}

In conclusion, about $3692.47 should be deposited.

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6 0
3 years ago
Read 2 more answers
I need help Please help.
asambeis [7]

Answer:

Step-by-step explanation:

Number of students 10

Problem 1. $625 for the bus hire per friday, So 625*4=$2500

Problem 2. 2500/25=$100 each for the whole 4 weeks

Problem 3.

10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each

20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each

30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each

41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each

Hope this is correct

8 0
3 years ago
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