Step 
<u>Find the slope of the given line</u>
Let
slope mAB is equal to
Step 
<u>Find the slope of the line that is perpendicular to the given line</u>
Let
CD ------> the line that is perpendicular to the given line
we know that
If two lines are perpendicular, then the product of their slopes is equal to 
so
Step 
<u>Find the equation of the line with mCD and the point (3,0)</u>
we know that
the equation of the line in the form point-slope is equal to
Multiply by both sides
therefore
the answer is
the equation of the line that is perpendicular to the given line is the equation
A 3 1/3
Subtract
8x-2-5x=8
-5x
3x-2=8
+2 +2
3x=8
X=10/3
8/3 cups or 2 2/3
2/3 × 4/1 = 8/3
if u divide 3 into 8 it gives u 2 times with 2 places left
the 2 places equal 2/3
2 whole OR 6/3 + 2/3 = 8/3 OR 2 and 2/3
You first wanna find <BAD, because if AB is perpendicular to AC, then it has to form a 90 degree angle. So 90-56=34 degrees. So now you have a 34 & 63 degrees in the ABD triangle. In a triangle, all angles add up to equal 180 degrees. So 34+63+x=180...and x=83. So <ADB= 83 degrees. Now you want to find angle ADC...which you can just subtract 83 from 180 (because <ADB & <ADC forms 180 degree angle). You will then get 97 as angle ADC. So, the same thing as before, add up 56+97+x=180, because all angles (in the triangle ADC) add up to be 180 degrees. X will then equal 27 degrees. Angle ACB= 27 degrees.
Answer:
<em>B is the correct answer</em>, The first choice (which you chose) is the incorrect answer.
Step-by-step explanation:
