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BARSIC [14]
3 years ago
15

Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 ​ p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus

, 5 p=p=p, equals
Mathematics
1 answer:
Ksivusya [100]3 years ago
7 0

Given:

The given equation is:

16-3p=\dfrac{2}{3}p+5

To find:

The value of p.

Solution:

We have,

16-3p=\dfrac{2}{3}p+5

Multiply both sides by 3.

3(16-3p)=3\left(\dfrac{2}{3}p+5\right)

48-9p=2p+15

Isolating the variable terms, we get

48-15=2p+9p

33=11p

Divide both sides by 11, we get

\dfrac{33}{11}=p

3=p

Therefore, the required solution is p=3.

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dsp73
The answer should be 18.66
7 0
3 years ago
What is the solution of 3x+9<15
Zolol [24]

Answer:

Third one

Step-by-step explanation:

<u>Two </u>things to solve      3x+9 <= 15

                                        3x <= 6

                                         <u> x <= 2</u>

      <u>   and</u>   - (3x+ 9) <= 15

                  - 3x - 9 <= 15

                   - 3x <= 24

                      3x >= -24

                     <u>   x > = - 8 </u>

<u />

<u />

<u>s o   -8 <= x <= 2 </u>

3 0
2 years ago
The balance in Al's account is $ 32.60 . The balance in Dee's account is 3 4 the balance in Al's account. The balance in Zac's a
shtirl [24]

Answer:

Balance in Zac's account = - $24.63

Step-by-step explanation:

Given:

Balance in Al's account = $32.60

Balance in Dee's account = 3/4 the balance in Al's account

Balance in Zac's account = balance in Dee's account - $49.08

Find:

Balance in Zac's account

Computation:

Balance in Dee's account = 3/4 the balance in Al's account

Balance in Dee's account = [3/4][32.60]

Balance in Dee's account = $24.45

Balance in Zac's account = balance in Dee's account - $49.08

Balance in Zac's account = $24.45 - $49.08

Balance in Zac's account = - $24.63

7 0
3 years ago
9 Four students were asked to write an expression that is
BabaBlast [244]

Answer:

Step-by-step explanation:

8x - 20.....factor a 4 out

4(2x - 5) <=== this one is correct...not 100% sure who wrote it

8x - 20...factor out a 2

2(4x - 10) <==== this is correct

8x - 20....factor out a -2

-2(-4x + 10) <==== this is correct

8x - 20....factor out a -4

-4(-2x + 5).....nobody did this one......but somebody tried....that person didn't factor correctly

8 0
3 years ago
Rationalize the denominator and simplify.
cestrela7 [59]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3151018

——————————
 
     \mathsf{\dfrac{3\sqrt{6}+5\sqrt{2}}{4\sqrt{6}-3\sqrt{2}}}


Multiply and divide by the conjugate of the denominator, which is  \mathsf{4\sqrt{6}+3\sqrt{2}:}

     \mathsf{=\dfrac{\big(3\sqrt{6}+5\sqrt{2}\big)\cdot \big(4\sqrt{6}+3\sqrt{2}\big)}{\big(4\sqrt{6}-3\sqrt{2}\big)\cdot \big(4\sqrt{6}+3\sqrt{2}\big)}}


Expand those products and eliminate the brackets:
 
     \mathsf{=\dfrac{\big(3\sqrt{6}+5\sqrt{2}\big)\cdot 4\sqrt{6}+ \big(3\sqrt{6}+5\sqrt{2}\big)\cdot 3\sqrt{2}}{\big(4\sqrt{6}-3\sqrt{2}\big)\cdot 4\sqrt{6}+ \big(4\sqrt{6}-3\sqrt{2}\big)\cdot 3\sqrt{2}}}\\\\\\ \mathsf{=\dfrac{12\cdot \big(\sqrt{6}\big)^2+20\sqrt{2}\cdot \sqrt{6}+9\cdot \sqrt{6}\cdot \sqrt{2}+15\cdot \big(\sqrt{2}\big)^2}{16\cdot \big(\sqrt{6}\big)^2-12\cdot \sqrt{2}\cdot \sqrt{6}+ 12\cdot \sqrt{6}\cdot \sqrt{2}-9\cdot \big(\sqrt{2}\big)^2}}\\\\\\ \mathsf{=\dfrac{12\cdot 6+20\sqrt{2\cdot 6}+9\sqrt{6\cdot 2}+15\cdot 2}{16\cdot 6-12\sqrt{2\cdot 6}+ 12\sqrt{6\cdot 2}-9\cdot 2}}\\\\\\ \mathsf{=\dfrac{72+20\sqrt{12}+9\sqrt{12}+30}{96-12\sqrt{12}+12\sqrt{12}-18}}

     \mathsf{=\dfrac{72+29\sqrt{12}+30}{96-18}}\\\\\\ \mathsf{=\dfrac{102+29\sqrt{2^2\cdot 3}}{78}}\\\\\\ \mathsf{=\dfrac{102+29\cdot \sqrt{2^2}\cdot \sqrt{3}}{78}}\\\\\\ \mathsf{=\dfrac{102+29\cdot 2\sqrt{3}}{78}} 

     \mathsf{=\dfrac{102+58\sqrt{3}}{78}}\\\\\\ \mathsf{=\dfrac{\,\diagup\!\!\!\! 2\cdot \big(51+29\sqrt{3}\big)}{\diagup\!\!\!\! 2\cdot 39}} 

     \mathsf{=\dfrac{51+29\sqrt{3}}{39}}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)

4 0
3 years ago
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