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postnew [5]
3 years ago
9

I need help on this plz

Mathematics
1 answer:
balandron [24]3 years ago
3 0

Answer:

(2) angle1 = 139, angle2 = 41, angle4 = 41, angle5 = 139, angle6 = 41, angle7 = 139, angle8 = 41

(3) angle1 = 150, angle2 = 30, angle4 = 30, angle5 = 150, angle6 = 30, angle7 = 150, angle8 = 30

Step-by-step explanation:

All angle are either equal to each other or supplementary.  I use corresponding angles and vertical angles to prove each of the above.

For number 3, angle 3 and angle 8 are supplementary, so they add up to 180:

8x +70 + (4x - 10) = 180

12x + 60 = 180

12x = 120

x = 10

So if x = 10, then 8x + 70 = 8(10) + 70 = 150

That means all angles are either 150 or 30 for number 3.

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Given: △ABC, m∠A=60°,<br> m∠C=45°, AB=9<br> Find: Perimeter of △ABC, <br> Area of △ABC
docker41 [41]

i hope my handwriting isnt too bad and that this helps!

6 0
3 years ago
Need help on this one too
DedPeter [7]

Answer:

sin(θ)=4√41/41

cos(θ)=5√41/41

tan(θ)=4/5

cot(θ)=5/4

sec(θ)=√41/5

csc(θ)=√41/4

Step-by-step explanation:

4 0
3 years ago
Solve for n: -1/2 (n + 8) +3/4
vlabodo [156]

\frac{1}{2} (n+8) + \frac{3}{4}

\frac{1(n+8)}{2}  +  \frac{3}{4}

\frac{n+8}{2}  +  \frac{3}{4}

\frac{2(n+8)}{4}  + \frac{3}{4}

\frac{2(n+8) + 3}{4}

\frac{2n + 16 +3}{4}

\frac{2n + 19}{4}

7 0
2 years ago
100 points please help
Eva8 [605]
V= b x h = 5 x 18 = 90ft
6 0
3 years ago
Read 2 more answers
20 points, please help
Damm [24]

Answer:

The answer to your question is:    83 + 6\sqrt{35}

Step-by-step explanation:

This is a square of a binomial.

                                  (2\sqrt{5} + 3\sqrt{7} )^{2}

1.- Square of the first term

                               ( 2\sqrt{5} )^{2} = 4(5) = 20

2.- Twice the product of the two terms

               (2)(2\sqrt{5} )(3\sqrt{7} ) = 6\sqrt{35}

3.- Square of the second term

                              (3\sqrt{7)})^{2} = 9(7) = 63

4.- Write the solution

                           20 + 6\sqrt{35} + 63

                            83 + 6\sqrt{35}

7 0
4 years ago
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