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Finger [1]
3 years ago
6

WILL MARK YOU IF YOU HELP ME !!!!

Mathematics
2 answers:
Tomtit [17]3 years ago
8 0

Answer:

perpendicular bisector

coldgirl [10]3 years ago
7 0

Answer:

Perpendicular bisector

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Two lines intersect in _____. one plane many planes one point many points
Effectus [21]
Two lines intersect in one point.
5 0
3 years ago
Read 2 more answers
What is 1 2/3 multiple 2/3
Flauer [41]

Answer:

1\frac{1}{9}

Step-by-step explanation:

Given the following question:

1\frac{2}{3} \times\frac{2}{3}

In order to multiply the two, we have to convert the mixed number into a improper fraction and then multiply the numerator by the numerator, the denominator by the denominator.

1\frac{2}{3} =3\times1=3+2=\frac{5}{3}
\frac{5}{3} \times\frac{2}{3}
5\times2=10
3\times3=9
=\frac{10}{9}

<u>Convert the improper fraction into a mixed number:</u>

\frac{10}{9}
\frac{10}{9} =10\div9=1\frac{1}{9}
=1\frac{1}{9}

Your answer is "1 1/9."

Hope this helps.

7 0
2 years ago
5. g(x) = 7x, find g(-7)
kompoz [17]

Answer:

just plug in

g(x)=7x

g(-7)=7*(-7)

7*(-7)=-49

Step-by-step explanation:

3 0
2 years ago
Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant, 
USPshnik [31]

By definition of tangent,

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

Recall the double angle identities:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

cos(2<em>θ</em>) = cos²(<em>θ</em>) - sin²(<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

where the latter equality follows from the Pythagorean identity, cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1. From this identity we can solve for the unknown value of sin(<em>θ</em>):

sin(<em>θ</em>) = ± √(1 - cos²(<em>θ</em>))

and the sign of sin(<em>θ</em>) is determined by the quadrant in which the angle terminates.

<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

sin(<em>θ</em>) = - √(1 - (-4/5)²) = -3/5

Then

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

tan(2<em>θ</em>) = (2 sin(<em>θ</em>) cos(<em>θ</em>)) / (2 cos²(<em>θ</em>) - 1)

tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

4 0
3 years ago
1. 3/5 divided by 7/12
scZoUnD [109]

\frac{3}{5}  \div  \frac{7}{12 }

=  \frac{3}{5}  \times  \frac{12}{7}

=  \frac{36}{35}

= 1 \frac{1}{35}

6 0
2 years ago
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