To multiply the imaginary number i, we still can use the product rule for exponents. When we multiply, we get
![i^{0+1+2+3+4}=i^{10}](https://tex.z-dn.net/?f=i%5E%7B0%2B1%2B2%2B3%2B4%7D%3Di%5E%7B10%7D)
.
Now, simplifying this might seem formidable at first. But, let's start working through different powers of i.
![i^0=1\\i^1=i\\i^2=-1\\i^3=-i\\i^4=(-1)(-1)=1](https://tex.z-dn.net/?f=i%5E0%3D1%5C%5Ci%5E1%3Di%5C%5Ci%5E2%3D-1%5C%5Ci%5E3%3D-i%5C%5Ci%5E4%3D%28-1%29%28-1%29%3D1)
Notice that
![i^4=1](https://tex.z-dn.net/?f=i%5E4%3D1)
. That means that any power that is a multiply of four will also be 1. For instance,
![i^8=1,\ i^{12}=1](https://tex.z-dn.net/?f=i%5E8%3D1%2C%5C%20i%5E%7B12%7D%3D1)
, and so on...
If we rewrite
![i^{10}](https://tex.z-dn.net/?f=i%5E%7B10%7D)
with this in mind, we can break it down into smaller pieces and simplify.
The answer is B.
Answer:
20.528
Step-by-step explanation:
So..number of times it can be squeezed=volume of tube
3.14*2.25*14=n*15 then solve for n.
98.91/15=n n=6.594 but you round to the nearest whole number so it would be 6 whole squeezes. hope i helped;)
Multiply 5x11, and add it to 5/11, to turn the number into a single fraction; 60/11. The reciprocal is this number flipped upside down, so the solution is 11/60.
Therefore the solution is 11/60.
Answer:
1 13 2 16 3 17 4 21
Step-by-step explanation:
i hope this helps