Answer:
b. When you divide both sides by 2x = 6x it could lead us to think that there is no solution while, in fact, the solution is x = 0.
Step-by-step explanation:
The solution is correct up to the step 2x = 6x
2x = 6x
Subtract 2x from both sides.
0 = 4x
Divide both sides by 4.
x = 0
You cannot divide both sides by x since x could be zero, and in fact, it is.
Answer: b. When you divide both sides by 2x = 6x it could lead us to think that there is no solution while, in fact, the solution is x = 0.
A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
8.454 is 3 tenths more than 8.154
3.625 is 2 and 2 tenths more than 1.425
Place values after the decimal point are tenths, hundredths, thousandths, ten thousandths...so on.
So 3 tenths looks like this 0.30 ⇒ 3 is in the tenths place. When you say 3 tenths more, it is a clue that the operation to be done is addition. thus,
8.154
<u>+ 0.30
</u> 8.454 * in addition or subtraction, the decimal points must be aligned to avoid confusion.
2 and 2 tenths is like this 2.20 ⇒ 1st 2 is in the ones or units place and the 2nd 2 is in the tenths place. Again it states more than so addition must be done.
1.425
<u>+ 2.20</u>
3.625
<u>
</u>
<span>4p−8 = 4 (p-2)
answer is </span><span>d. 4 (p-2)</span>
i dont quite get the question but...
i guess this is how it is.
Take the mirror image of∆ABC Through the a line through the point y=3.
The new ∆ABC would have point C=(4,2)
B=(3,-6) A=(1,-3)
Now shifting the ∆ABC one unit (<em>i.e. 2 acc. to the graph as scale is 1 unit =2</em>) towards right ( or <em>adding 2 to the x coordinates of ∆ABC)</em>
We get the Coordinates of triangle ABC as A=(3,-3) B=(5,-6) C=(6,2).
This coordinate is the same coordinates of ∆A"B"C".
Hope it helps...
Regards;
Leukonov/Olegion.
