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ivanzaharov [21]
2 years ago
6

a badly weighed 7.25 lbs at birth at the end of 8 months the baby weighted 2\1/2 time it birth weight how many pounds did the ba

by weigh at the end if 8 months​
Mathematics
1 answer:
sashaice [31]2 years ago
8 0

Answer:rkrllr

Step-by-step explanation:

Jdejkeke

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Jordan is 27 miles short of his biking goal. Hayden went 27 miles over his goal. Which of the following statement is true?​
agasfer [191]

Answer:

Option A

Step-by-step explanation:

Jordan is 27 miles short of his biking goal.

This statement states that Jordan is 27 miles behind the goal.

Hayden went 27 miles over his goal.

This statement states that Hayden is 27 miles ahead of his goal.

Option A

Both are 27 miles away from their goal.

True.

Option B

Since, both were 27 miles away from their goal,

Statement is False.

Option C

Since, the goal was same both,

Given statement is False.

Option D

Goal was same for both Jordan and Hayden,

Statement is False.

5 0
3 years ago
Can someone help me with this one
rewona [7]
4 over 5 or y=4/5x+0
5 0
3 years ago
Helppppppppp!!!!!!!!
Pavlova-9 [17]

Answer:

The answer is D

Step-by-step explanation:

4 0
3 years ago
What is a solutions of x^2-2x+10=0?​
Debora [2.8K]

Answer:

x = 1± 3i

Step-by-step explanation:

x^2-2x+10=0

We can complete the square to solve by subtracting 10 from each side

x^2-2x+10-10=-10

x^2 -2x = -10

We need to add (2/2) ^2  to each side or 1

x^2 -2x+1 = -10 +1

x^2 -2x+1 = -9

The left side factors into (x- (2/2) ) ^2

(x-1) ^2 = -9

Take the square root of each side

sqrt((x-1) ^2 =± sqrt(-9)

x-1 = ±sqrt(-1) sqrt(3)

Remember the sqrt(-1) = i

x-1 = ± 3i

Add 1 to each side

x-1+1 = 1± 3i

x = 1± 3i

8 0
2 years ago
Find all x ∈ Z satisfying each of the following equations.3x = 2 (mod 7)
Vlada [557]

Answer:

7x−3=7k,x=7k+3,k∈ℤ

Step-by-step explanation:

3x ≡ 2 (mod 7)

3 is a solution, since 3×3−2=7.

All solutions are 3+7ℤ

y=3x−2/7=3(x−3)+7/7=3(x−3)/7+1

7x−3=7k,x=7k+3,k∈ℤ

5 0
2 years ago
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