complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
Using the midpoint formula we get:
(x,y)=(0+5/2, 0+12/2) or (5/2, 6) as the midpoint.
Answer:
The answer is C
Step-by-step explanation: because it is reflecting and is backwards.
Answer:
The value of x any y are "-5.29 and 0.79" and "3.79 and -2.29"
Step-by-step explanation:
Given values:
After solve equation (a) we get
After solve equation (b) we get
put the value of x in to equation (x)
The value of y is = -5.29 and 0.79, put the value of y in x1 equation so, we get: 3.79 and -2.29
