Answer:
Hey There!
Let's solve....
Radius=5cm
Angle = pi/3
Therefore arc length= Radius×angle
The arc length is 5.23 cm when Theta=pi/ 3 and radius is 5 cm.
<h2>I hope it is helpful to you...</h2><h3>Cheers!_________</h3>
Answer:3(x-9) is expressed as 3x-27
Step-by-step explanation: 3(Xminus9)
3(X-9)
Use 3 to open the bracket by using 3 to multiply everything in the bracket.
Then you will get
3x-27
V=x(8-2x)(10-2x) or expanded
V=x(4x^2-36x+80)
V=4x^3-36x^2+80x
...
If you were to graph the above equation for V(x) you will see a maximum point where the "y" value is maximized, but be careful as V will increase without bound at values of x that are not part of the domain, ie, in this case x<8/2, x<4 to have any meaning...The proper domain of this function is:
x=(0,4), Mathematically finding this point quickly is by differentiating it with respect to x...
dV/dx=12x^2-72x+80, The maximum volume will occur when dV/dx=0 and the x value is within the correct domain...
12x^2-72x+80=0 (using the quadratic formula for ease)
x=(72±√1344)/24, and since x<4
x≈1.472in (to the nearest one thousandth of an inch)
There is no given below but it will have a slope intersept form of o my friend
is the expression that represents the perimeter of rectangle
<em><u>Solution:</u></em>
Let "x" represent the width of rectangle
Given that length of rectangle is 3 units shorter than one-third of the width x
length of rectangle = one-third of the width x - 3
<em><u>The perimeter of rectangle is given as:</u></em>
<h3>perimeter of rectangle = 2(length + width)</h3>
Substituting the known values we get,
Thus perimeter of rectangle is
Thus option 1 is correct
