A. To increase productivity in the future
Answer:
Organisms such as hydra use regenerative cells for reproduction in the process of budding. In hydra, a bud develops as an outgrowth due to repeated cell division at one specific site. These buds develop into tiny individuals and, when fully mature, detach from the parent body and become new independent individuals.
Explanation:
The correct answer is true
Answer:
The correct answer would be 1/32
Explanation:
Mary and Justin can have affected child only when both of them are carriers that is, both of them should be Gg.
The probability of Justin's father to be a carrier is 2/4 or 1/2 [1 GG: 2Gg: 1gg].
Similarly, the probability of Jean to be a carrier would be 1/2.
Thus, the probability of Justin and his father to be a carrier would be equal to 1/2*1/2 ⇒ 1/4.
The probability of Mary to be a carrier = 1/2.
So, the probability of Mary and Justin to be the carrier of the disease would be 1/2*1/4 = 1/8.
Now, the probability of having an affected child would be 1/4 as it is a recessive disorder.
So, the probability of Mary and Justin to have an affected child = 1/4 * 1/8 ⇒ 1/32
Answer:
3) Condensación del agua en la naturaleza
El vapor de agua sólo se condensará en otra superficie cuando ésta sea más fría que la temperatura del vapor de agua, o cuando el equilibrio de vapor de agua en el aire, es decir, la humedad de saturación, se haya excedido.
Explanation:
