(8x-4)+(17x-23)+(3x+17)=180

How to write 3 turnovers : 12assists as a fraction in simplest form

ArbitrLikvidat [17]

3/ 12 hope this helps as much as it can

3 0

4 years ago

PLEASE HELP ME!! I need you to solve this inequality. 2/3x - 1/5 > 1

Verizon [17]

Answer:

If you are trying to solve the inequality for "x" Then your answer is, "x>9/5" That is the inequality form. If you are looking for the interval notation form then your answer is "9/5, infinity"

Step-by-step explanation:

I have checked my answers against an online Algebra solver. So my answers are 100% correct.

PLEASE MARK BRAINLIEST

7 0

3 years ago

angel has 4/8 yard of ribbon and Lynn has 3/4 yard of ribbon. do angel and Lynn have the same amount of ribbon

Licemer1 [7]

No, as Anglel has 0.5 yards and Lynn has 0.75 yards

5 0

3 years ago

Read 2 more answers

Find the common denominator 5/10 and 2/5

grigory [225]

Rewrite input as fractions:
5/10, 2/5

For the denominators (10, 5) the least common multiple is 10.

The least common denominator least common multiple is 10.

Rewrite the original inputs as equivalent fractions with the least common multiple: 5/10, 4/10

Your answer for your question is 10.

5 0

3 years ago

Read 2 more answers

the company also discovered that it costs 30 to 2 widgets, 118 to produce 4 and 766 to produce 10 widgets. Find the total cost o

miv72 [106K]

We will first write cost function. As we are given three points here so we will use them to write quadratic function

$y = ax^{2} +bx+c$ ----------------------------------------(1)

So we will plug point (2,30) in it first ( for 2 widgets cost is 30)

So simply plug 30 in y place and 2 in x place in equation (1) as shown

$30 = a(2)^{2} +b(2)+c$

$30 = 4a +2b +c$ ----------------------------------------------(2)

Similarly plug next point (4,118) now in equation (1)

$118 = a(4)^{2} +b(4)+c$

$118 = 16a +4b +c$ ----------------------------------------------(3)

Similarly plug third point (10,766) now in equation (1)

$766 = a(10)^{2} +b(10)+c$

$766 = 100a +10b +c$ ----------------------------------------------(4)

Now we have to solve system of linear equations (2),(3) and (4) for a,b,c

We can use method of elimination

Subtract equation (3) - equation (2)

118 = 16a +4b +c

-(30 = 4a +2b +c)

----------------------------------------------------

88 = 12a +2b -----------------------------------(5)

Similarly subtract equation (4)-equation (3)

766 =100a +10b +c

-( 118 = 16a +4b +c)

--------------------------------------

648 = 84a + 6b ------------------------(6)

Now to eliminate b in equations (5) and (6) multiply equation (5) by -3 and then add to equation (6)

-3×(88 = 12a +2b)

-264 = -36a - 6b

648 = 84a + 6b

---------------------------------

384 = 48a

Now solve for a

$\frac{384}{48} = \frac{48a}{48}$

8 = a

Plug 8 in a place in equation (5) or (6) and solve for b as shown

88 = 12(8) +2b

88 = 96 + 2b

88 -96 = 96 +2b -96

-8 = 2b

$\frac{-8}{2} = \frac{2b}{2}$

-4 = b

now plug 8 in a place, -4 in b place in either of equations (2),(3) or (4) and solve for c

30 = 4(8) +2(-4) +c

30 = 32 -8 + c

30 = 24 + c

30 - 24 = 24 + c - 24

6 = c

So plugging values of a as 8, b as -4 and c as 6 in equation (1) we get

$y = 8x^{2} -4x+ 6$

So thats the cost function. So now for 6 widgets, plug 6 in x place in this equation and find y value

$y = 8(6)^{2} -4(6)+ 6$

y = 8(36) - 24 +6

y = 288 -24 +6

y = 270

So $270 is the cost for producing 6 widgets and thats the final answer

4 0

3 years ago