The coordinates of A, B, and C in the diagram are A (p, 4), B (6, 1 ), and C (9, q). Which equation correctly relates p and q? ↔
↔ ↔ ↔ Hint: Since AB is perpendicular to BC, the slope of AB × the slope o BC = -1. A. -q − p = 7 B. q − p = 7 C. p − q = 7 D. p + q = 7
1 answer:
Answer:
D. p + q = 7
Step-by-step explanation:
The slope of AB is ...
mAB = (y2 -y1)/(x2 -x1) = (1 -4)/(6 -p) = -3/(6 -p)
The slope of BC is ...
mBC = (q -1)/(9 -6) = (q -1)/3
We want the product of these slopes to be -1:
mAB·mBC = -1 = (-3/(6 -p))·((q -1)/3)
-(q-1)/(6 -p) = -1 . . . . cancel factors of 3
q -1 = 6 -p . . . . . multiply by -(6 -p)
q + p = 7 . . . . . matches choice D
You might be interested in
Answer:
I don't really know the answer because I don't
Step-by-step explanation:
Answer:
Step-by-step explanation:
Yes 6 over 9 simplifys to 2 over 3.
And 4 over 6 simplifys down to 2 over 3
Can I have brainliest please :D
the correct answer is 24:10
Answer:
$325
Step-by-step explanation
78% is 234
x is 100%
cross multiply
= 
234 × 100 = 72x
23400 = 72x
23400÷72 =72x ÷72
325 = x
Answer:
h=3in
Step-by-step explanation:
A=a+b
2h
Solving forh
h=2A
a+b=2·13.5
3+6=3in
