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2 years ago

I need help if you can help me plz I would really appreciate it ?

Mathematics

2 answers:

olya-2409 [2.1K]2 years ago

7 0

Answer:

Step-by-step explanation:

(1, 5),

(8, - 16)

m = ( - 16 - 5 ) / (8 - 1) = - 3

y - 5 = - 3(x - 1)

<em>y = ( - 3)x + 8</em>

Greeley [361]2 years ago

5 0

Y=-3x+8 by using slope intercept form

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Keith_Richards [23]

Answer:

the law of cosines with ABC

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1 year ago

I need help please and thank you

myrzilka [38]

Answer:

Step-by-step explanation:

Slope = y2- y1/ x2- x1

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2 years ago

Triangle ABC has angle measures as shown below. Using the information in the

iren [92.7K]

35 + 52 + 3(x + 2) = 180
87 + 3x + 6 = 180 ( add the like terms and use distributive property)
93 + 3x = 180
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2 years ago

Read 2 more answers

which of these shows the result of using the first equation to substitute for y in the second equation, then combining like term

Furkat [3]

Answer:

C. $\Rightarrow \bold{8x = 16}$

Step-by-step explanation:

Given the two equations:

$y=2x ........ (1)\\ 2x+3y=16.......(2)$

To find:

The correct option when value of y is substituted to 2nd equation using the 1st equation.

Solution:

First of all, let us learn about the substitution method.

Substitution method is the method to provide solutions to two variables when we have two equations and two variables.

In substitution method, we find the value of one variable in terms of the other variable and put this value in the other equation.

Now, the other equation becomes only single variable and then we solve for the variable's value.

Here, we have two equations and value of one varible is:

$y=2x$

Let us put value of y in 2nd equation:

$2x+3y=16\\\Rightarrow 2x + 3(2x) = 16\\\Rightarrow 2x + 6x = 16\\\Rightarrow \bold{8x=16}$

So, the correct answer is option C. $\Rightarrow \bold{8x = 16}$

7 0

3 years ago

(cot^2x - 1)/(csc^2x) = cos2x

Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

$cos(2x)=cos^2x-sin^2x$ ,

$cos(2x)=1-2sin^2x$ , and

$cos(2x)=2cos^2x-1$

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants. Rewriting gives you:

$\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

$\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

$\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}$

And canceling out the sin^2 x leaves us with just

$cos^2x-sin^2x$ which is one of our identities.

5 0

2 years ago