Answer:
6.69
Step-by-step explanation:
The hundredths place is two decimal places to the right. This lands you at 8, so you must look at the number after it to determine whether you round up or down. So you look at 5, which rounds the 8 up to 9. Therefore, it is 6.69
The inequality n <span>≥ 9 properly represents the graph because the arrow is pointing to the right of 9, and the dot is filled in on 9, representing Greater than or equal to.
Hope that helped!</span>
Answer:
![\displaystyle log_\frac{1}{2}(64)=-6](https://tex.z-dn.net/?f=%5Cdisplaystyle%20log_%5Cfrac%7B1%7D%7B2%7D%2864%29%3D-6)
Step-by-step explanation:
<u>Properties of Logarithms</u>
We'll recall below the basic properties of logarithms:
![log_b(1) = 0](https://tex.z-dn.net/?f=log_b%281%29%20%3D%200)
Logarithm of the base:
![log_b(b) = 1](https://tex.z-dn.net/?f=log_b%28b%29%20%3D%201)
Product rule:
![log_b(xy) = log_b(x) + log_b(y)](https://tex.z-dn.net/?f=log_b%28xy%29%20%3D%20log_b%28x%29%20%2B%20log_b%28y%29)
Division rule:
![\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20log_b%28%5Cfrac%7Bx%7D%7By%7D%29%20%3D%20log_b%28x%29%20-%20log_b%28y%29)
Power rule:
![log_b(x^n) = n\cdot log_b(x)](https://tex.z-dn.net/?f=log_b%28x%5En%29%20%3D%20n%5Ccdot%20log_b%28x%29)
Change of base:
![\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20log_b%28x%29%20%3D%20%5Cfrac%7B%20log_a%28x%29%7D%7Blog_a%28b%29%7D)
Simplifying logarithms often requires the application of one or more of the above properties.
Simplify
![\displaystyle log_\frac{1}{2}(64)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20log_%5Cfrac%7B1%7D%7B2%7D%2864%29)
Factoring
.
![\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20log_%5Cfrac%7B1%7D%7B2%7D%2864%29%3D%5Cdisplaystyle%20log_%5Cfrac%7B1%7D%7B2%7D%282%5E6%29)
Applying the power rule:
![\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20log_%5Cfrac%7B1%7D%7B2%7D%2864%29%3D6%5Ccdot%20log_%5Cfrac%7B1%7D%7B2%7D%282%29)
Since
![\displaystyle 2=(1/2)^{-1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%202%3D%281%2F2%29%5E%7B-1%7D)
![\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})](https://tex.z-dn.net/?f=%5Cdisplaystyle%20log_%5Cfrac%7B1%7D%7B2%7D%2864%29%3D6%5Ccdot%20log_%5Cfrac%7B1%7D%7B2%7D%28%281%2F2%29%5E%7B-1%7D%29)
Applying the power rule:
![\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})](https://tex.z-dn.net/?f=%5Cdisplaystyle%20log_%5Cfrac%7B1%7D%7B2%7D%2864%29%3D-6%5Ccdot%20log_%5Cfrac%7B1%7D%7B2%7D%28%5Cfrac%7B1%7D%7B2%7D%29)
Applying the logarithm of the base:
![\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cdisplaystyle%20log_%5Cfrac%7B1%7D%7B2%7D%2864%29%3D-6%7D)
Answer:
93107
Step-by-step explanation:
add all of the numbers together
divide by 5 since there are 5 numbers
you would get 92106.8
so round that up since you cannot have 1/8 of a squirrel
Hope this helps!!