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scZoUnD [109]
3 years ago
13

Which expression is equivalent to 17s - 10 + 3(2s + 1)

Mathematics
2 answers:
Nikitich [7]3 years ago
7 0

Answer:

23s-7

Step-by-step explanation:

tino4ka555 [31]3 years ago
5 0
The answer to 17s-10+3(2s+1) is 23s-7
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4 years ago
Wayne's service center operates a welding shop. Assume that the arrival of jobs follows a Poisson distribution with 2 jobs arriv
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Answer:

a) 0.3125 per hour

b) 2.225 hours

c) 8.9 hours

d) 12.1 hours

e) 80%

Step-by-step explanation:

Given that:

mean time = 3.2 hours, standard deviation (σ) = 2 hours

The  mean service rate in jobs per hour (λ) = 2 jobs/ 8 hour = 0.25 job/hour

a) The average number of jobs waiting for service (μ)= 1/ mean time = 1/ 3.2 = 0.3125 per hour

b) The average time a job waits before the welder can begin working on it (L) is given by:

L=\frac{\lambda^2\sigma^2+(\lambda/\mu)^2}{2(1-\lambda/\mu))} =\frac{0.25^2*0.2^2+(0.25/0.3125)^2}{2(1-0.25/0.3125)}=2.225\ hours

c) The average number of hours between when a job is received and when it is completed (Wq) is given as:

W_q=\frac{L}{\lambda}=2.225/0.25=8.9\ hours

d) The average number of hours between when a job is received and when it is completed (W) is given as:

W=W_q+\frac{1}{\mu} =8.9+\frac{1}{0.3125}=12.1 \ hours

e) Percentage of the time is Gubser's welder busy (P) is given as:

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3 years ago
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Step-by-step explanation:

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4 years ago
Suppose that a company prints baseball cards. They claim that 30% of the cards feature rookies, 60% feature veterans, and 10% fe
liraira [26]

Answer:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

Step-by-step explanation:

On this case we need to apply a Chi squared goodness of fit test, and the correct system of hypothesis would be:

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Ha: At least one of the proportions in the null hypothesis is false.

And in order to test it we need to have observed and expected values. On this case we  can calculate the Expected values like this

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And if the p value it's higher than the significance level we FAIL to reject the null hypothesis. In other case we reject the null hypothesis.

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3 years ago
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