What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L container at 25.0°C?
1 answer:
Answer:
1.2218 atm
Step-by-step explanation:
From ideal gas formula,
PV=nRT
Where n= number of moles
V= volume
T= temperature=25.0°C
= (273 + 25) = 298 K
R= gas constant = 0.082 l atm /K mol.
Making P subject of formula we have
P= [nRT] /V
Then substitute the values we have
P= [0.5 x 0.082 x 298] / 10
P= 1.2218 atm
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