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3 years ago

What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L container at 25.0°C?

Mathematics

1 answer:

drek231 [11]3 years ago

6 0

Answer:

1.2218 atm

Step-by-step explanation:

From ideal gas formula,

PV=nRT

Where n= number of moles

V= volume

T= temperature=25.0°C

= (273 + 25) = 298 K

R= gas constant = 0.082 l atm /K mol.

Making P subject of formula we have

P= [nRT] /V

Then substitute the values we have

P= [0.5 x 0.082 x 298] / 10

P= 1.2218 atm

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Mr. Ayer cuts one melon into 8 equal pieces. write the number 1 as a sum unit fractions that name each piece of melon.

sertanlavr [38]

It would split up in eighths. So it would be like 1/8, 2/8, 3/8 ....

6 0

3 years ago

The United States government used to make coins of many different values

Papessa [141]

Answer:

1. 50%

2. 3%

3. 20%

4. 200%

Step-by-step explanation:

Here, we want to find the worth of each coin as a percentage of $1

We simply divide the worth by $1 and multiply by 100%

$1 is same as 100 cents

Thus;

1. 50 cent

= 50/100 * 100% = 50%

2. 3 cents

= 3/100 * 100% = 3%

3. 20 cents

= 20/100 * 100% = 20%

4. $2

= 2/1 * 100% = 200%

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2 years ago

Don’t remember how to do this , ?

andriy [413]

28. The ratio of games they won to total games played = 12: 14 = 6: 7.

29. Max's pay rate is 9.50 dollars per hour.

30. The value of n is 9.

Step-by-step explanation:

Step 1; Heather's team won 12 games out of 14. To find the ratio of games won to the total number of games we divide the number of games won to the number of games played.

The ratio of games won to games played = 12: 14, dividing both sides by 2 we simplify the ratio. So the simplified ratio is 6: 7.

Step 2; Max earns $380 for working 40 hours. So to find how much he earns an hour we divide the total money earned in n hours divided by n number of hours.

Money earned per hour = $\frac{380}{40}$ = $9.50. So Max's pay rate per hour is $9.50.

Step 3; The given proportion is

$\frac{n}{12}$ = $\frac{18}{24}$ , to solve this we keep n on the left-hand side while we multiply the 12 on to the other side

n = $\frac{18}{24}$ × 12 = $\frac{3}{4}$ × 12 = $\frac{36}{4}$ = 9.

7 0

2 years ago

In March 2015, the Public Policy Institute of California (PPIC) surveyed 7525 likely voters living in California. This is the 14

lbvjy [14]

Answer:

We are confident at 99% that the difference between the two proportions is between $0.380 \leq p_{Republicans} -p_{Democrats} \leq 0.420$

Step-by-step explanation:

Part a

Data given and notation

$X_{D}=3266$ represent the number people registered as Democrats

$X_{R}=2137$ represent the number of people registered as Republicans

$n=7525$ sampleselcted

$\hat p_{D}=\frac{3266}{7525}=0.434$ represent the proportion of people registered as Democrats

$\hat p_{R}=\frac{2137}{7525}=0.284$ represent the proportion of people registered as Republicans

The standard error is given by this formula:

$SE=\sqrt{\frac{\hat p_D (1-\hat p_D)}{n_{D}}+\frac{\hat p_R (1-\hat p_R)}{n_{R}}}$

And the standard error estimated given by the problem is 0.008

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion of Democrats that approve of the way the California Legislature is handling its job

$\hat p_A =\frac{1894}{3266}=0.580$ represent the estimated proportion of Democrats that approve of the way the California Legislature is handling its job

$n_A=3266$ is the sample size for Democrats

$p_B$ represent the real population proportion of Republicans that approve of the way the California Legislature is handling its job

$\hat p_B =\frac{385}{2137}=0.180$ represent the estimated proportion of Republicans that approve of the way the California Legislature is handling its job

$n_B=2137$ is the sample for Republicans

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.