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svetlana [45]
3 years ago
10

What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L container at 25.0°C?

Mathematics
1 answer:
drek231 [11]3 years ago
6 0

Answer:

1.2218 atm

Step-by-step explanation:

From ideal gas formula,

PV=nRT

Where n= number of moles

V= volume

T= temperature=25.0°C

= (273 + 25) = 298 K

R= gas constant = 0.082 l atm /K mol.

Making P subject of formula we have

P= [nRT] /V

Then substitute the values we have

P= [0.5 x 0.082 x 298] / 10

P= 1.2218 atm

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We know that the area of a circle is equal to \pir^{2}.

A semi-circle is a half-circle, meaning that it will have half of the area of a full circle.

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We then find that r = 6.

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Plug 6 in for r.

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