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svetlana [45]
3 years ago
10

What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L container at 25.0°C?

Mathematics
1 answer:
drek231 [11]3 years ago
6 0

Answer:

1.2218 atm

Step-by-step explanation:

From ideal gas formula,

PV=nRT

Where n= number of moles

V= volume

T= temperature=25.0°C

= (273 + 25) = 298 K

R= gas constant = 0.082 l atm /K mol.

Making P subject of formula we have

P= [nRT] /V

Then substitute the values we have

P= [0.5 x 0.082 x 298] / 10

P= 1.2218 atm

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Answer:

The first number (x) = 8

Step-by-step explanation:

Let x = the first number

Let y = the second number

x = 3*y - 4

2x + 3 - 2y = 11        Subtract 3 from both sides

2x - 2y = 11 - 3

2x - 2y = 8              Divide by 2

x - y = 4                   Add y to both sides

x = y + 4                  Now go back to the very first equation. Substitute for x

y + 4 = 3y - 4          Subtract y from both sides

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8/2 = y

y = 4

x = 3y - 4

x = 3*4 - 4

x = 12 - 4

x = 8

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Step-by-step explanation:

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In order to raise funds to attend upcoming competitions, the debate team is selling hot chocolate at a football game. They hope
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Step-by-step explanation:

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<em>Hope this helped! Have a good day.</em>

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