It’s 3y not just 3. You need to add the exponent as well
Answer:

The problem:
Find
if
,
, and
.
Step-by-step explanation:


Replace
in
with
since we are asked to find
:
![\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
![\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
This implies that 
Let's check:



![\sqrt[3]{(x+1)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28x%2B1%29%2B2%7D)
![\sqrt[3]{x+1+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D)
which is the required result for
.
It’s all too big and I love the kids and the gator is the
Factor -20x+32
which comes out to 4(-5x+8)
answer: 4(-5x+8)
hope this helped :)
Answer: a. Radius of circle = 
b. The equation of this circle :
Step-by-step explanation:
Given : Center of the circle = (3,10)
Circle is passing through (12,12).
a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)
Radius of circle = 
Radius of circle = 
i.e. Radius of circle = 
b. Equation of a circle =
, where (h,k)=Center and r=radius of the circle.
Put the values of (h,k)= (3,10) and r=
, we get
∴ The equation of this circle :